Pls suggest
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- prachi18oct
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I made a clumsy calculation mistake and got it wrong. However I want to verify my reasoning.
Ca = concetration of chemical A
Cb = concetration of chemical B
rate = k (Ca ^2)
rate = k' (1/ Cb)
Now if the Cb is increased by 100% i.e it is doubled, the rate becomes half.
To maintain the rate constant it has to be multiplied by a factor of 2 . So the concentration of A has to be increased as it is directly proprtional . A, B, C are out.
40% increase means new conc of A is 1.4 Ca. Squaring it is 1.96 Ca ~ 2 Ca hence doubled.
50% increase means teh new con of A is 1.5 Ca . Squaring it will give 2.25 Cb which is less approximate than the D option.
Hence D.
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Hi prachi18oct,
You approach is correct. Beyond the algebraic concepts and using the answers to your advantage, you could also have TESTed VALUES to confirm the solution.
GMAT assassins aren't born, they're made,
Rich
You approach is correct. Beyond the algebraic concepts and using the answers to your advantage, you could also have TESTed VALUES to confirm the solution.
GMAT assassins aren't born, they're made,
Rich