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Please Help!

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Kobe_Kassidy Just gettin' started! Default Avatar
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Please Help! Post Mon Aug 06, 2012 9:10 am
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    New Member here. This place looks amazing!

    Here's my problem

    If (1/5)^m X (1/4)^18 = 1/2(10)^35, what is m?

    I apologize I don't have all the answer choices. All I know is that the answer is m = 35

    How do you get this answer?

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    Post Mon Aug 06, 2012 11:49 am
    Hey, how's it going? Welcome the the Beat the GMAT community. If you have not done so, you should definitely try searching this question since it has probably been posted often. However, I will provide a solution.

    (1/5)^m x (1/4)^ 18 = 1/(2(10^35))

    Notice that 1/(2(10^35)) = 1/(2*(2*5)^35)) = 1/(2*(2^35)*(5^35)) = 1/(2^36*5^35)

    Also, note that (1/4)^18 = (1/(2^2))^18 = 1/(2^36)

    So we have:

    (1/5)^m x 1/(2^36) = 1/(2^36) x 1/(5^35)

    From comparing both sides, looks like m = 35.

    Hope that helps!

    Remember some of your exponent properties for this problem:
    (x^a)^b = x^(ab)
    (x/y)^a = (x^a)/(y^a)

    Thanked by: Kobe_Kassidy
    Kobe_Kassidy Just gettin' started! Default Avatar
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    Post Mon Aug 06, 2012 12:43 pm
    That is awesome! Thank you!

    Some of those properties of exponents questions have been killing me.

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