Welcome! Check out our free B-School Guides to learn how you compare with other applicants.

This topic has 5 member replies
KingTmo Just gettin' started!
Joined
31 Jan 2010
Posted:
25 messages
Thanked:
1 times
Elapsed Time: 00:00
• Lap #[LAPCOUNT] ([LAPTIME])
Please help with this as the GMAC problems have no solution. I know its easy but, I still need help!!! Thanks

Need free GMAT or MBA advice from an expert? Register for Beat The GMAT now and post your question in these forums!
amising6 Really wants to Beat The GMAT!
Joined
05 May 2010
Posted:
292 messages
Thanked:
54 times
Target GMAT Score:
790
Sat Jun 19, 2010 12:56 pm
KingTmo wrote:
Please help with this as the GMAC problems have no solution. I know its easy but, I still need help!!! Thanks
(8^2)(3^3)(2^4)/(96^2)
8^2= (2*2*2)^2=(2^3)^2=2^6 (since (a^m)^n=a^mn)

96^2=(2*2*2*2*2*3)^2=(2^5*3)^2=2^10* 3^2

now (8^2)(3^3)(2^4)/(96^2)
(2^6)(3^3)(2^4)/2^10* 3^2 (a^b+a^c =a(b+c))
2^10*3^3/2^10* 3^2
=3

_________________
Ideation without execution is delusion

Thanked by: KingTmo
intellijat Just gettin' started!
Joined
16 May 2010
Posted:
4 messages
Mon Jun 21, 2010 7:47 am
Quote:
hi........
it would do you a world of good to memorize squares/cubes of numbers at least up to 20

8^2=8*8=64
3^3=3*3=27
2^4=2*2*2*2=16
96^2=96*96
simply solve to get the the answer=3

also remember
2^2=4
2^3=8
2^4=16
2^5=32
2^6=64
can you see the relation ?

dinesh19aug Rising GMAT Star
Joined
21 Feb 2008
Posted:
78 messages
Thanked:
7 times
Mon Jul 12, 2010 3:38 pm
For solving this question you should not multiply the numbers. There is quick way and smart way(if you are not able to do it quick)

Quick way : As intellijat mentioned above. However if you do not remember the square of the number then do not make the mistake of mutiplying (8^2)(3^3)(2^4)/(96^2) .

For this sort of quetion you can simply reduce it to simplest fraction and and divide in parts. EX - 8^2 / 2^2

8 * 8 / 2 * 2 = 4 * 4 = 16.

You can do the same for the actual problem as well.

ankitc Just gettin' started!
Joined
14 Jul 2010
Posted:
1 messages
Wed Jul 14, 2010 12:55 am
its simple....first check the highest numbers.....8^2 and 96^2

now 96/8=12, so in d denominator we have 12^2 instead of 96 if we factor out 8 from the numerator

2^4 = 4^2 now that goes very well with 12^2 in the denom.........giving us 3^2
So we are now left with

3^3/ 3^2 = 3 very simple.......voila!! Cheers

strivedi Just gettin' started!
Joined
02 Feb 2011
Posted:
2 messages
Test Date:
4/27/2012
Target GMAT Score:
640
Sat Apr 21, 2012 9:09 pm
For this problem easiest way was to simplify using the exponent rule:
(8^2)(3^3)(2^4)/(96^2)

This can be rewritten in powers of 2 by the following, 96 has the prime factorization of 2^5 x 3:
[(2^3)^2 } (3^3)(2^4)/(2^5*3)^2

Now combine like terms and powers:
2^(6+4) (3^3)/(2^10*3^2)

Here the 2^10 can cancel out and we're left with:
3^3/3^2
which leaves us with answer of 3

### Best Conversation Starters

1 varun289 40 topics
2 guerrero 21 topics
3 sana.noor 20 topics
4 killerdrummer 19 topics
5 sanaa.rizwan 14 topics
See More Top Beat The GMAT Members...

### Most Active Experts

1 Brent@GMATPrepNow

GMAT Prep Now Teacher

203 posts
2 GMATGuruNY

The Princeton Review Teacher

140 posts
3 Jim@StratusPrep

Stratus Prep

100 posts
4 Anju@Gurome

Gurome

99 posts