Permutation and combination-Boys and Girls

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Find the number of ways 5 boys and 4 girls can be seated in a row.
2 girls cannot sit together


Answer option was 43200

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by Brent@GMATPrepNow » Fri May 02, 2014 7:53 am
s91arvindh wrote:Find the number of ways 5 boys and 4 girls can be seated in a row.
2 girls cannot sit together
Take the task of seating the 9 children and break it into stages.

Stage 1: Arrange the 5 boys in a row (in 5 ADJACENT chairs)
There's a nice rule that says we can arrange n unique objects in a row in n! ways.
So, we can complete stage 1 in 5! ways (120 ways)

IMPORTANT: Now place a chair on either side of each boy to get:
_B_B_B_B_B_
These are the "girl chairs" Notice that this ENSURES that no two girls sit together.

Stage 2: Seat one of the girls
There are 6 chairs, so we can complete this stage in 6 ways.

Stage 3: Seat another girl
There are now 5 chairs remaining digits, so we can complete this stage in 5 ways.

Stage 4: Seat another girl
There are now 4 chairs remaining digits, so we can complete this stage in 4 ways.

Stage 5: Seat the last girl
There are now 3 chairs remaining digits, so we can complete this stage in 3 ways.

By the Fundamental Counting Principle (FCP), we can complete all 5 stages (and thus seat all 9 children) in (120)(6)(5)(4)(3) ways ([spoiler]= 43,200 ways[/spoiler])

--------------------------

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Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by s91arvindh » Fri May 02, 2014 8:10 am
Brent@GMATPrepNow wrote:
s91arvindh wrote:Find the number of ways 5 boys and 4 girls can be seated in a row.
2 girls cannot sit together
_B_B_B_B_B_
These are the "girl chairs" Notice that this ENSURES that no two girls sit together.

Thanks a lot for your reply !

I am confused with the question now. Since it was said no two girls sit together , doesn't it mean that other 2 girls should sit together?

For example :

GBGBGGBBB