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Operation on rational numbers

This topic has 3 expert replies and 1 member reply
saadishah Junior | Next Rank: 30 Posts Default Avatar
Joined
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Operation on rational numbers

Post Thu Dec 03, 2015 1:15 am
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    An OG question

    Q. At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day
    crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the
    two crews did the day crew load?

    (A) 1/2
    (B) 2/5
    (C) 3/5
    (D) 4/5
    (E) 5/8

    Don't really follow the explanation given in the OG.

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    Post Thu Dec 03, 2015 3:11 am
    Quote:
    At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load?

    (A) 1/2

    (B) 2/5

    (C) 3/5

    (D) 4/5

    (E) 5/8
    Day crew:
    Let the number of workers = 5.
    Let the number of boxes loaded by each worker = 4.
    Total number of boxes loaded = 5*4 = 20.

    Night crew:
    Since the night crew has 4/5 as many workers as the day crew, the number of workers on the night crew = (4/5)5 = 4.
    Since each worker on the night crew loads 3/4 as many boxes as each worker on the day crew, the number of boxes loaded by each night crew worker = (3/4)4 = 3.
    Total number of boxes loaded = 4*3 = 12.

    (Boxes loaded by the day crew)/(Total number of boxes loaded by the two crews) = 20/(20+12) = 20/32 = 5/8.

    The correct answer is E.

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    Post Thu Dec 03, 2015 10:12 am
    HI saadishah,

    TESTing VALUES (the approach that Mitch used) is a fairly easy way to work through this question. If you want to use an Algebraic approach, then that's fine, but you have to be very careful about what your variables represent.

    The number of night workers is related to the number of day workers...

    IF...
    N = number of night workers
    D = number of day workers

    N = (4/5)D

    Next, you have to create a variable and an equation for the number of boxes loaded per employee.

    B = number loaded per day worker
    (3/4)B = number loaded per night worker

    Now we can set up a ratio of boxes loaded by the Day workers to TOTAL boxes loaded by all workers:

    (D)(B) / [ (D)(B) + (N)(3/4)(B) ]

    Since N = (4/5)D, we can substitute in that value...

    DB / [DB + (4/5)(D)(3/4)(B)]

    Next, we can multiply and simplify...

    DB / [DB + (12/20)DB]
    DB / (32/20)DB]
    1 / [32/20]

    20/32 = 5/8

    Final Answer: E

    GMAT assassins aren't born, they're made,
    Rich

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    Post Thu Dec 03, 2015 10:14 am
    Quote:
    At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load?


    A. 1/2
    B. 2/5
    C. 3/5
    D. 4/5
    E. 5/8

    I think the fast way is to plug in some nice numbers.
    Since the two pieces of information regarding the night shift are related to the information regarding the day shift, let's assign some nice values to the DAY shift.

    Number of workers

    Day shift: 5 workers (this is an easy number to find 4/5 of)
    Night shift: 4 workers (4/5 of 5 = 4)

    Boxes loaded per worker
    Day shift: 4 boxes per worker
    Night shift: 3 boxes per worker (3/4 of 4 = 3)

    Total boxes loaded
    Day shift: 5 workers times 4 boxes per worker = 20 boxes
    Night shift: 4 workers times 3 boxes per worker = 12 boxes

    Combined total boxes for both shifts = 20 + 12 = 32

    Of the 32 boxes, the day shift loaded 20 of them.
    20/32 = 5/8

    Answer: E

    Cheers,
    Brent

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    vishnujthattil Newbie | Next Rank: 10 Posts Default Avatar
    Joined
    12 Jan 2016
    Posted:
    2 messages
    Post Wed Jan 13, 2016 10:02 am
    saadishah wrote:
    An OG question

    Q. At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day
    crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the
    two crews did the day crew load?

    (A) 1/2
    (B) 2/5
    (C) 3/5
    (D) 4/5
    (E) 5/8

    Don't really follow the explanation given in the OG.
    As given in the problem night crew loaded 3/4 boxes and there are 4/5 workers as compared to day crew, so in effect their work is 3/4 * 4/5= 3/5 times the day crew's work, which means the ratio of night crew's work to day crew's work is 3:5. That easily gives the fraction of work by day crew, i.e 5/(3+5) = 5/8.

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