A committee is composed of w women and m men. If 3 women and 2 men are added to the committee, and if one person is selected at random from the enlarged committee, then the probability that a woman is selected can be represented by
(A) w/m
(B) w/(w+m)
(C) (w+3)/(m+2)
(D) (w+3)/(w+m+3)
(E) (w+3)/(w+m+5)
OA: E
Hello, Experts! Please explain how to solve the problem. Thanks a lot.
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OG2015 PS A committee is composed
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lionsshare
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Jay@ManhattanReview
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After the inclusion of 3 women and 2 men, there are (w + 3) women and (m + 2) men in the committee.lionsshare wrote:A committee is composed of w women and m men. If 3 women and 2 men are added to the committee, and if one person is selected at random from the enlarged committee, then the probability that a woman is selected can be represented by
(A) w/m
(B) w/(w+m)
(C) (w+3)/(m+2)
(D) (w+3)/(w+m+3)
(E) (w+3)/(w+m+5)
OA: E
Hello, Experts! Please explain how to solve the problem. Thanks a lot.
So there are a total of (w + 3 + m + 2) = (w + m +5) persons in the committee
We have to select one person such that the selected person is a woman.
Probability that the person is woman = (Total number of woman) / (Total number of persons)
Probability that the person is woman = (w + 3) / (w + m + 5)
The correct answer: E
Hope this helps!
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Brent@GMATPrepNow
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A committee is composed of w women and m men. If 3 women and 2 men are added to the committee . . .lionsshare wrote:A committee is composed of w women and m men. If 3 women and 2 men are added to the committee, and if one person is selected at random from the enlarged committee, then the probability that a woman is selected can be represented by
(A) w/m
(B) w/(w+m)
(C) (w+3)/(m+2)
(D) (w+3)/(w+m+3)
(E) (w+3)/(w+m+5)
After the 3 women and 2 men are added, we have...
w+3 women and m+2 men
. . . and if one person is selected at random from the enlarged committee, then the probability that a woman is selected can be represented by
P(select woman) = (# of women in committee)/(TOTAL # of people on committee)
= (w+3)/(w+3 + m+2 )
= (w+3)/(w+m+5)
Answer: E
Cheers,
Brent
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Hi lionsshare,
This question is perfect for TESTing VALUES. We're told that a committee is composed of W women and M men.
IF...
W = 2
M = 3
3 women and 2 men are then ADDED to the committee.....
Women = 2+3 = 5
Men = 3+2 = 5
The question asks for the probability of selecting a woman from this larger group:
5 women and 10 total people --> 5/10
So we're looking for an answer that = 5/10 = 1/2 when W=2 and M=3
Answer A: 2/3 NOT a match
Answer B: 2/(2+3) = 2/5 NOT a match
Answer C: (2+3)/(3+2) = 5/5 NOT a match
Answer D: (2+3)/(2+3+3) = 5/8 NOT a match
Answer E: (2+3)/(2+3+5) = 5/10 This IS a match
Final Answer: E
GMAT assassins aren't born, they're made,
Rich
This question is perfect for TESTing VALUES. We're told that a committee is composed of W women and M men.
IF...
W = 2
M = 3
3 women and 2 men are then ADDED to the committee.....
Women = 2+3 = 5
Men = 3+2 = 5
The question asks for the probability of selecting a woman from this larger group:
5 women and 10 total people --> 5/10
So we're looking for an answer that = 5/10 = 1/2 when W=2 and M=3
Answer A: 2/3 NOT a match
Answer B: 2/(2+3) = 2/5 NOT a match
Answer C: (2+3)/(3+2) = 5/5 NOT a match
Answer D: (2+3)/(2+3+3) = 5/8 NOT a match
Answer E: (2+3)/(2+3+5) = 5/10 This IS a match
Final Answer: E
GMAT assassins aren't born, they're made,
Rich
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Jeff@TargetTestPrep
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To solve the problem, we recall that:lionsshare wrote:A committee is composed of w women and m men. If 3 women and 2 men are added to the committee, and if one person is selected at random from the enlarged committee, then the probability that a woman is selected can be represented by
(A) w/m
(B) w/(w+m)
(C) (w+3)/(m+2)
(D) (w+3)/(w+m+3)
(E) (w+3)/(w+m+5)
OA: E
probability = (number of favorable outcomes)/(total number of outcomes)
In the problem, we are asked the probability of selecting a woman. In the enlarged committee, there are (w + 3) women and there are (m + 2) men, making the total number of people (w + 3 + m + 2) = (w + m + 5).
Thus, the probability of selecting a woman is:
(w + 3)/(w + m + 5)
Answer: E
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