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OG2015 PS A committee is composed

This topic has 4 expert replies and 0 member replies
lionsshare Senior | Next Rank: 100 Posts
Joined
09 Aug 2017
Posted:
62 messages

OG2015 PS A committee is composed

Post Wed Sep 13, 2017 7:42 pm
A committee is composed of w women and m men. If 3 women and 2 men are added to the committee, and if one person is selected at random from the enlarged committee, then the probability that a woman is selected can be represented by

(A) w/m
(B) w/(w+m)
(C) (w+3)/(m+2)
(D) (w+3)/(w+m+3)
(E) (w+3)/(w+m+5)

OA: E

Hello, Experts! Please explain how to solve the problem. Thanks a lot.

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Top Reply
Post Tue Sep 19, 2017 2:56 pm
lionsshare wrote:
A committee is composed of w women and m men. If 3 women and 2 men are added to the committee, and if one person is selected at random from the enlarged committee, then the probability that a woman is selected can be represented by

(A) w/m
(B) w/(w+m)
(C) (w+3)/(m+2)
(D) (w+3)/(w+m+3)
(E) (w+3)/(w+m+5)

OA: E
To solve the problem, we recall that:

probability = (number of favorable outcomes)/(total number of outcomes)

In the problem, we are asked the probability of selecting a woman. In the enlarged committee, there are (w + 3) women and there are (m + 2) men, making the total number of people (w + 3 + m + 2) = (w + m + 5).

Thus, the probability of selecting a woman is:

(w + 3)/(w + m + 5)

Answer: E

_________________
Jeffrey Miller Head of GMAT Instruction

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Top Reply
Post Thu Sep 14, 2017 11:10 am
Hi lionsshare,

This question is perfect for TESTing VALUES. We're told that a committee is composed of W women and M men.

IF...
W = 2
M = 3

3 women and 2 men are then ADDED to the committee.....

Women = 2+3 = 5
Men = 3+2 = 5

The question asks for the probability of selecting a woman from this larger group:

5 women and 10 total people --> 5/10

So we're looking for an answer that = 5/10 = 1/2 when W=2 and M=3

Answer A: 2/3 NOT a match
Answer B: 2/(2+3) = 2/5 NOT a match
Answer C: (2+3)/(3+2) = 5/5 NOT a match
Answer D: (2+3)/(2+3+3) = 5/8 NOT a match
Answer E: (2+3)/(2+3+5) = 5/10 This IS a match

Final Answer: E

GMAT assassins aren't born, they're made,
Rich

_________________
Contact Rich at Rich.C@empowergmat.com

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Post Tue Sep 19, 2017 2:56 pm
lionsshare wrote:
A committee is composed of w women and m men. If 3 women and 2 men are added to the committee, and if one person is selected at random from the enlarged committee, then the probability that a woman is selected can be represented by

(A) w/m
(B) w/(w+m)
(C) (w+3)/(m+2)
(D) (w+3)/(w+m+3)
(E) (w+3)/(w+m+5)

OA: E
To solve the problem, we recall that:

probability = (number of favorable outcomes)/(total number of outcomes)

In the problem, we are asked the probability of selecting a woman. In the enlarged committee, there are (w + 3) women and there are (m + 2) men, making the total number of people (w + 3 + m + 2) = (w + m + 5).

Thus, the probability of selecting a woman is:

(w + 3)/(w + m + 5)

Answer: E

_________________
Jeffrey Miller Head of GMAT Instruction

  • +1 Upvote Post
  • Quote
  • Flag
Post Thu Sep 14, 2017 11:10 am
Hi lionsshare,

This question is perfect for TESTing VALUES. We're told that a committee is composed of W women and M men.

IF...
W = 2
M = 3

3 women and 2 men are then ADDED to the committee.....

Women = 2+3 = 5
Men = 3+2 = 5

The question asks for the probability of selecting a woman from this larger group:

5 women and 10 total people --> 5/10

So we're looking for an answer that = 5/10 = 1/2 when W=2 and M=3

Answer A: 2/3 NOT a match
Answer B: 2/(2+3) = 2/5 NOT a match
Answer C: (2+3)/(3+2) = 5/5 NOT a match
Answer D: (2+3)/(2+3+3) = 5/8 NOT a match
Answer E: (2+3)/(2+3+5) = 5/10 This IS a match

Final Answer: E

GMAT assassins aren't born, they're made,
Rich

_________________
Contact Rich at Rich.C@empowergmat.com

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