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OG2015 PS A committee is composed

This topic has 4 expert replies and 0 member replies
lionsshare Senior | Next Rank: 100 Posts
Joined
09 Aug 2017
Posted:
62 messages

OG2015 PS A committee is composed

Post Wed Sep 13, 2017 7:42 pm
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    A committee is composed of w women and m men. If 3 women and 2 men are added to the committee, and if one person is selected at random from the enlarged committee, then the probability that a woman is selected can be represented by

    (A) w/m
    (B) w/(w+m)
    (C) (w+3)/(m+2)
    (D) (w+3)/(w+m+3)
    (E) (w+3)/(w+m+5)

    OA: E

    Hello, Experts! Please explain how to solve the problem. Thanks a lot.

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    Post Wed Sep 13, 2017 9:22 pm
    lionsshare wrote:
    A committee is composed of w women and m men. If 3 women and 2 men are added to the committee, and if one person is selected at random from the enlarged committee, then the probability that a woman is selected can be represented by

    (A) w/m
    (B) w/(w+m)
    (C) (w+3)/(m+2)
    (D) (w+3)/(w+m+3)
    (E) (w+3)/(w+m+5)

    OA: E

    Hello, Experts! Please explain how to solve the problem. Thanks a lot.
    After the inclusion of 3 women and 2 men, there are (w + 3) women and (m + 2) men in the committee.

    So there are a total of (w + 3 + m + 2) = (w + m +5) persons in the committee

    We have to select one person such that the selected person is a woman.

    Probability that the person is woman = (Total number of woman) / (Total number of persons)

    Probability that the person is woman = (w + 3) / (w + m + 5)

    The correct answer: E

    Hope this helps!

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    Post Thu Sep 14, 2017 6:43 am
    lionsshare wrote:
    A committee is composed of w women and m men. If 3 women and 2 men are added to the committee, and if one person is selected at random from the enlarged committee, then the probability that a woman is selected can be represented by

    (A) w/m
    (B) w/(w+m)
    (C) (w+3)/(m+2)
    (D) (w+3)/(w+m+3)
    (E) (w+3)/(w+m+5)
    A committee is composed of w women and m men. If 3 women and 2 men are added to the committee . . .
    After the 3 women and 2 men are added, we have...
    w+3 women and m+2 men

    . . . and if one person is selected at random from the enlarged committee, then the probability that a woman is selected can be represented by
    P(select woman) = (# of women in committee)/(TOTAL # of people on committee)
    = (w+3)/(w+3 + m+2 )
    = (w+3)/(w+m+5)

    Answer: E

    Cheers,
    Brent

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    Post Thu Sep 14, 2017 11:10 am
    Hi lionsshare,

    This question is perfect for TESTing VALUES. We're told that a committee is composed of W women and M men.

    IF...
    W = 2
    M = 3

    3 women and 2 men are then ADDED to the committee.....

    Women = 2+3 = 5
    Men = 3+2 = 5

    The question asks for the probability of selecting a woman from this larger group:

    5 women and 10 total people --> 5/10

    So we're looking for an answer that = 5/10 = 1/2 when W=2 and M=3

    Answer A: 2/3 NOT a match
    Answer B: 2/(2+3) = 2/5 NOT a match
    Answer C: (2+3)/(3+2) = 5/5 NOT a match
    Answer D: (2+3)/(2+3+3) = 5/8 NOT a match
    Answer E: (2+3)/(2+3+5) = 5/10 This IS a match

    Final Answer: E

    GMAT assassins aren't born, they're made,
    Rich

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    Post Tue Sep 19, 2017 2:56 pm
    lionsshare wrote:
    A committee is composed of w women and m men. If 3 women and 2 men are added to the committee, and if one person is selected at random from the enlarged committee, then the probability that a woman is selected can be represented by

    (A) w/m
    (B) w/(w+m)
    (C) (w+3)/(m+2)
    (D) (w+3)/(w+m+3)
    (E) (w+3)/(w+m+5)

    OA: E
    To solve the problem, we recall that:

    probability = (number of favorable outcomes)/(total number of outcomes)

    In the problem, we are asked the probability of selecting a woman. In the enlarged committee, there are (w + 3) women and there are (m + 2) men, making the total number of people (w + 3 + m + 2) = (w + m + 5).

    Thus, the probability of selecting a woman is:

    (w + 3)/(w + m + 5)

    Answer: E

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