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OG2015 DS Paula and Sandy were

This topic has 2 expert replies and 0 member replies
lionsshare Senior | Next Rank: 100 Posts
Joined
09 Aug 2017
Posted:
62 messages

OG2015 DS Paula and Sandy were

Post Sat Sep 16, 2017 10:25 pm
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    Paula and Sandy were among those people who sold raffle tickets to raise money for Club X. If Paula and Sandy sold a total of 100 of the tickets, how many of the tickets did Paula sell?

    (1) Sandy sold 2/3 as many of the raffle tickets as Paula did.
    (2) Sandy sold 8 percent of all the raffle tickets sold for Club X.

    OA: A

    Anyone, please what's the best approach to solving this problem.

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    Post Sun Sep 17, 2017 7:35 am
    lionsshare wrote:
    Paula and Sandy were among those people who sold raffle tickets to raise money for Club X. If Paula and Sandy sold a total of 100 of the tickets, how many of the tickets did Paula sell?

    (1) Sandy sold 2/3 as many of the raffle tickets as Paula did.
    (2) Sandy sold 8 percent of all the raffle tickets sold for Club X.

    OA: A

    Anyone, please what's the best approach to solving this problem.
    Statement 1: Sandy sold 2/3 as many of the raffle tickets as Paula did.

    Say Paula sold x tickets, thus Sandy sold 2x/3 tickets.

    Thus, x + 2x/3 = 100

    x = 60. Sufficient.

    Statement 2: Sandy sold 8 percent of all the raffle tickets sold for Club X.

    We do not have any information about how many tickets Paula sold. This information does not help. Insufficient.

    The correct answer: A

    Hope this helps!

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    Post Sun Sep 17, 2017 7:43 am
    lionsshare wrote:
    Paula and Sandy were among those people who sold raffle tickets to raise money for Club X. If Paula and Sandy sold a total of 100 of the tickets, how many of the tickets did Paula sell?

    (1) Sandy sold 2/3 as many of the raffle tickets as Paula did.
    (2) Sandy sold 8 percent of all the raffle tickets sold for Club X.
    Target question: How many of the tickets did Paula sell?

    Given: Paula and Sandy sold a total of 100 of the tickets
    Let x = number of tickets that Paula sold
    This means 100-x = number of tickets that Sandy sold

    Statement 1: Sandy sold 2/3 as many of the raffle tickets as Paula did.
    We can write: (# of tickets Sandy sold) = (2/3)(# of tickets Paula sold)
    Or... 100-x = (2/3)x
    Eliminate the fractions by multiplying both sides by 3 to get: 300 - 3x = 2x

    ASIDE: At this point, we should recognize that we CAN solve this equation for x, which means we CAN answer the target question with certainty. But for "fun" let's finish the math...

    Add 3x to both sides to get: 300 = 5x
    Solve: x = 60
    In other words, Paula sold 60 tickets
    Since we can answer the target question with certainty, statement 1 is SUFFICIENT

    Statement 2: Sandy sold 8 percent of all the raffle tickets sold for Club X.
    We don't know how many tickets were sold for Club X. All we know is that Paula and Sandy sold a total of 100 tickets.
    Since we don't know how many tickets were sold for Club X, we can't determine the number of tickets Sandy sold.
    If we can't determine the number of tickets Sandy sold, then we can't determine the number of tickets Paula sold.
    Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

    Answer: A

    Cheers,
    Brent

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