OG Quant Review: DS, Chapter 5.5, Problem 117 wrong?
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One thing I can tell here is andle BCA = 2x. Now this (interior angle) will be equal to the sum of the two exterior angles that is angle ABC + angle ADC. Probably this is how OG is telling angle ABD is x.
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okay i struggled enuf on this to solve, finally it all boils down to this one theorem:
An exterior angle of a triangle is equal in measure to the sum of the two non-adjacent interior angles of the triangle
1. since <BDC=<BCD ==> BD=BC
2. now apply the above theorem to triangle BAD ==> <BDC = <BAC + <ABD
2x=x+y ==> x=y
3. Since, x=y implies that "side AD= side DB= side BC"
4. it is given in option A that AD=6 ==> side BC=6
5. Hence answer is A
An exterior angle of a triangle is equal in measure to the sum of the two non-adjacent interior angles of the triangle
1. since <BDC=<BCD ==> BD=BC
2. now apply the above theorem to triangle BAD ==> <BDC = <BAC + <ABD
2x=x+y ==> x=y
3. Since, x=y implies that "side AD= side DB= side BC"
4. it is given in option A that AD=6 ==> side BC=6
5. Hence answer is A