Official GMAT Prep Exam 5 Question

This topic has expert replies
Master | Next Rank: 500 Posts
Posts: 199
Joined: Sat Apr 26, 2014 10:53 am
Thanked: 16 times
Followed by:4 members
GMAT Score:780

Official GMAT Prep Exam 5 Question

by 800_or_bust » Fri Jun 17, 2016 12:24 pm
For the cube shown below, what is the degree measure of Angle PQR?

(a) 30
(b) 45
(c) 60
(d) 75
(e) 90

OA: C
Attachments
Cube PQR.png
Last edited by 800_or_bust on Fri Jun 17, 2016 12:27 pm, edited 1 time in total.
800 or bust!

Master | Next Rank: 500 Posts
Posts: 199
Joined: Sat Apr 26, 2014 10:53 am
Thanked: 16 times
Followed by:4 members
GMAT Score:780

by 800_or_bust » Fri Jun 17, 2016 12:26 pm
So I got this as Question 37 (of 37). I can't recall having seen a similar question in my studies (i.e. one that asks for an angle measure in three dimensions), so I was kind of at loss. I guessed what might be the most obvious answer, but it was wrong. And I'm still having a difficult time conceptualizing the correct answer. Any insight?
800 or bust!

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pm
Location: Vancouver, BC
Thanked: 5254 times
Followed by:1268 members
GMAT Score:770

by Brent@GMATPrepNow » Fri Jun 17, 2016 12:33 pm
800_or_bust wrote:For the cube shown below, what is the degree measure of Angle PQR?

(a) 30
(b) 45
(c) 60
(d) 75
(e) 90

OA: C
If we draw a line connecting points P and R, we see we that triangle PQR must be an equilateral triangle, which means all 3 angles (including angle PQR) must be 60 degrees each.

Answer: C
Brent Hanneson - Creator of GMATPrepNow.com
Image

GMAT/MBA Expert

User avatar
Elite Legendary Member
Posts: 10392
Joined: Sun Jun 23, 2013 6:38 pm
Location: Palo Alto, CA
Thanked: 2867 times
Followed by:511 members
GMAT Score:800

by [email protected] » Fri Jun 17, 2016 2:58 pm
Hi 800_or_bust,

Certain questions on Test Day are easier to solve if you 'play around' and do work in 'small pieces.'

In this prompt, you don't have much to work with, but you should notice that the two line segments are both DIAGONALS. Since we're dealing with a cube, those two diagonals would be the SAME length.

From there, you might think...since those two are the SAME length, if I formed a triangle with them, then that triangle would be ISOSCELES. That deduction, in and of itself, isn't that meaningful... BUT it should get you thinking about forming a triangle using those two line segments....

Drawing a quick sketch and including that new line segment across the "top" of the cube will help you to notice that that third line is ALSO a diagonal that has the SAME length as the other two line segments.

NOW you have a triangle with 3 equal sides... THAT is an EQUILATERAL triangle and determining the angle isn't very hard at all at that point.

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pm
Location: Vancouver, BC
Thanked: 5254 times
Followed by:1268 members
GMAT Score:770

by Brent@GMATPrepNow » Fri Jun 17, 2016 3:04 pm
Rich makes a good point about playing around and doing work in small pieces.
Here are two videos with this and other strategies to consider when tackling geometry questions on the GMAT:

GMAT Geometry Strategies - Part I: https://www.gmatprepnow.com/module/gmat ... /video/864

GMAT Geometry Strategies - Part II: https://www.gmatprepnow.com/module/gmat ... /video/885

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image

Master | Next Rank: 500 Posts
Posts: 415
Joined: Thu Oct 15, 2009 11:52 am
Thanked: 27 times

by regor60 » Mon Jun 20, 2016 10:33 am
800_or_bust wrote:So I got this as Question 37 (of 37). I can't recall having seen a similar question in my studies (i.e. one that asks for an angle measure in three dimensions), so I was kind of at loss. I guessed what might be the most obvious answer, but it was wrong. And I'm still having a difficult time conceptualizing the correct answer. Any insight?
What the other guys said and you can view this as an equilateral triangle rotated 45 degrees about an axis parallel with PR going through point Q

GMAT Instructor
Posts: 2630
Joined: Wed Sep 12, 2012 3:32 pm
Location: East Bay all the way
Thanked: 625 times
Followed by:119 members
GMAT Score:780

by Matt@VeritasPrep » Thu Jun 23, 2016 4:11 pm
Draw diagonal PR. Since each side of the triangle is a diagonal of the same length -- they each are diagonals of the same-sized square -- each of the triangle is the same, making it equilateral, with angles of 60°.

Neat Q, very typical GMAT: you can solve it in 5 seconds with the right approach (and minimal math!), but it can take an eternity if you don't think to draw the line.

User avatar
Senior | Next Rank: 100 Posts
Posts: 64
Joined: Tue May 22, 2012 10:44 pm
Thanked: 1 times

by evs.teja » Wed Jun 29, 2016 2:07 pm
Brent@GMATPrepNow wrote:
800_or_bust wrote: the cube shown below, what is the degree measure of Angle PQR?

(a) 30
(b) 45
(c) 60
(d) 75
(e) 90

OA: C
If we draw a line connecting points P R, we see we that triangle PQR must be an equilateral triangle, which means all 3 angles (including angle PQR) must be 60 degrees each.

Answer: C
Dear Brent,
I understood your solution but am in a dilemma, No matter whichever method I use I should get the same answer right ?
When I tried to solve this question via this method am getting 90 degrees , which is wrong but am not able to find out exactly where am I going in the wrong direction.
If I consider PQS as a triangle where S is corner between point P R.
I know a fact that it is an isosceles triangle
where angle PSR= 90
PS = SQ
therefore Angle SPQ = Angle SQP = 45
If I apply the same theory to triangle RSQ
Angle RQS = Angle SRQ = 45

Now Angle PQR = Angle PQS + Angle RQS = 90

Now I know this is wrong, sorry asking you such a dumb question :(.
But it will be really great if you help me out.

Regards
Teja.