If S is a series of x consecutive odd integers and Z is the larget integer in S, what is the smallest integer in S.

If S is a series of x consecutive odd integers and Z is the larget integer in S, what is the smallest integer in S.
1) Z-2x
2)Z-x+1
3)Z-2(x-1)
4)x-6+Z
5)Z- (x/2)
How can I solve this algebraically?

If S is a series of x consecutive odd integers and Z is the largest integer in S, what is the smallest integer in S.

1) Z-2x
2)Z-x+1
3)Z-2(x-1)
4)x-6+Z
5)Z- (x/2)


How can I solve this algebraically?

Agreed .But plugging in numbers are pretty easy.

take ,5,7,9.....

HereZ=9,x=3

We know that our smallest number is 5.

Plug in the values of Z & X.

1.Z-2x
--->9- 2*3=3( Not 5, which is required)

2.Z-x+1
---> 9-3+1=7(Not the answer we want)

3.Z-2(x-1)
--->9-2(3-1)=5(Bingo! we got answer smallest integer)

Thank you for this explanation. Looks easier when it has been layed out logically. Was going round in circles and had to post something. thanks for all the responses thus far. I prefer to solve with algebra than plugging numbers where possible