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smallsorrow
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PostPosted: Sat Oct 11, 2008 9:24 am    Post subject: number properties / functions Reply with quote

For which of the following functions is f(a+b)=f(a)+f(b) for all positive numbers a and b
A) f(x)=x^2
B) f(x)=x+1
C) f(x)=sq r x
D) f(x) =2/x
E) f(x)=-3x

Pls share your thoughts....

Thank you!
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vivek.kapoor83
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PostPosted: Sat Oct 11, 2008 9:30 am    Post subject: Reply with quote

IMO E.
coz f(a+b) = f(a)+f(b)
we have to prove.,
then
putiing x=a+b in E
f(a+b) = -3(a+b) = -3a-3b
put x = a
f(a) = -3a
put x =b
f(b) = -3b
f(a)+f(b) = -3a-3b

Hence,E.
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PostPosted: Sat Oct 11, 2008 9:44 am    Post subject: Reply with quote

It should be E

This ha sbeen solved in this forum before but cant find the link

Pick numbers lets say a=2 b=3

f(5) = f(2) + f(3)

x=5, x=2,x=3 WEvaluate the choices and E will be true
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smallsorrow
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PostPosted: Sat Oct 11, 2008 10:44 am    Post subject: Reply with quote

e is correct. thanks for explaining!
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elmiko
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PostPosted: Sat Oct 11, 2008 3:45 pm    Post subject: Reply with quote

cramya wrote:
It should be E

This ha sbeen solved in this forum before but cant find the link

Pick numbers lets say a=2 b=3

f(5) = f(2) + f(3)

x=5, x=2,x=3 WEvaluate the choices and E will be true


I don't understand how you plug in the choices into each of the functions in the answer choices. Can you explain further?
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canuckclint
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PostPosted: Sat Oct 11, 2008 5:58 pm    Post subject: Reply with quote

elmiko wrote:
cramya wrote:
It should be E

This ha sbeen solved in this forum before but cant find the link

Pick numbers lets say a=2 b=3

f(5) = f(2) + f(3)

x=5, x=2,x=3 WEvaluate the choices and E will be true


I don't understand how you plug in the choices into each of the functions in the answer choices. Can you explain further?


You can plug for example
f(x) = x^2 take a = 2 b = 3
f(a+b) = f(5) = 5^2
not equal to
f(a) + f(b) = f(2) + f(3) = 2^2 + 3^2

Actually there is no need to plug if you got the right answer.
Just remember factoring from algebra.

k(a+b) = ka + kb for any k. just from algebra
Part E is just sucah a case with k=-3

Cheers,
Clinton
Math Minor
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