Problem Solving

Hi fambrini,

Although the prompt does not state it, you are expected to know that each station wagon has 4 tires and each motorcycle has 2 tires. You might find it easiest to treat this algebraically:

W = number of station wagons
M = number of motorcycles

Total vehicles = W + M
Total tires = 4W + 2M

The number of tires is 30 more than twice the number of vehicles...

4W + 2M = 30 + 2(W+M)

Now we can combine like terms and simplify:

4W + 2M = 30 + 2W + 2M
2W = 30
W = 15

Final Answer: B

GMAT assassins aren't born, they're made,
Rich

fambrini wrote:A dealer owns a group of station wagons and motorcycles. If the number of tires (excluding spare tires) on the vehicles is 30 more than twice the number of vehicles, then the number of station wagons the dealer owns is

A) 10
B) 15
C) 20
D) 30
E) 45

OA: B

To start we can define some variables:

w = the number of station wagons

m = the number of motorcycles

Since there are 4 tires on a station wagon and 2 tires on a motorcycle, the number of tires per station wagon is 4w and the number of tires per motorcycle is 2m.

We are given that the number of tires (excluding spare tires) on the vehicles is 30 more than twice the number of vehicles so we can create the following equation:

4w + 2m = 30 + 2(w + m)

4w + 2m = 30 + 2w + 2m

2w = 30

w = 15

Thus, there are 15 station wagons at the dealership.

Answer: B