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by ronnie1985 » Thu Mar 29, 2012 9:38 am
S1: Sufficient
S2: y is an integer => y = 0 as y = x+mod x

(D)
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by Lifetron » Sun Aug 19, 2012 9:59 pm
Rezinka wrote:If y is an integer and y = |x| + x, is y=0?
(1) x<0
(2) y<1

OA : D
IMO : A

[spoiler]I don't think B gives me a definite value because the question only mentions y is an integer.
Case 1 : x = 0; So y = 0......... SUFFICIENT
Case 2 : x = 0.4; So y = 0.8... INSUFFICIENT[/spoiler]
Y can only be an integer. So, Case 2 is also SUFFICIENT

Answer is D
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by Ganesh hatwar » Fri Sep 07, 2012 2:03 am
A is tempting as it requires some analysis to to know if a works

as y is integer Ans D

but it becomes challenging during exam if it question after 28 and you have shortage of time
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by chris558 » Thu Sep 13, 2012 6:22 am
Missed that one too!
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by eski » Tue Sep 18, 2012 11:23 am
plotting on a line works gr8 here..... try it
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by Java_85 » Thu Oct 17, 2013 8:47 am
D it is.
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by jaspreetsra » Sat Dec 06, 2014 12:20 am
My answer:A
But correct is D.:(
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by GMATGuruNY » Sat Dec 06, 2014 4:17 am
Rezinka wrote:If y is an integer and y = |x| + x, is y=0?
(1) x<0
(2) y<1
Statement 1: x<0
If x = -1, then y = |-1| + (-1) = 0.
If x = -1/2, then y = |-1/2| + (-1/2) = 0.
If x=-10, then y = |-10| + (-10) = 0.
In every case, y=0.
SUFFICIENT.

Statement 2: y<1
The cases tested in statement 1 illustrate that y cannot be negative.
Since y must be an nonnegative integer less than 1, y=0.
SUFFICIENT.

The correct answer is D.
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