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mynn
Just gettin' started!
Joined: 15 Apr 2008
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Location: Malaysia
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 Posted: Tue Jul 22, 2008 1:36 am Post subject: Mixture Problem |
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Hi,
I always have a problem with a mixture problem..I really do not have any idea how to solve this question.
A CERTAIN QUANTITY OF 40% SOLUTION IS REPLACED WITH 25% SOLUTION SUCH THAT THE NEW CONCENTRATION IS 35%. WHAT IS THE FRACTION OF THE SOLUTION THAT WAS REPLACED?
A. 1/4
B. 1/3
C. 1/2
D. 2/3
E. 3/4
Please explain. TQ |
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sudhir3127
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Location: INDIA
Target GMAT Score: 700+
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| Posted: Tue Jul 22, 2008 4:03 am Post subject: |
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let x be the fraction replaced. if x is the fraction then the total is 1.
(1-x)*40 + x*25 = 35
40 - 40x + 25x = 35
5 = 15x
x = 1/3 |
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