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Register now and save up to $200 Available with Beat the GMAT members only code • 1 Hour Free BEAT THE GMAT EXCLUSIVE Available with Beat the GMAT members only code • Free Veritas GMAT Class Experience Lesson 1 Live Free Available with Beat the GMAT members only code • 5 Day FREE Trial Study Smarter, Not Harder Available with Beat the GMAT members only code • Get 300+ Practice Questions 25 Video lessons and 6 Webinars for FREE Available with Beat the GMAT members only code • Free Trial & Practice Exam BEAT THE GMAT EXCLUSIVE Available with Beat the GMAT members only code mixture problem. please hep with simple solution This topic has 2 expert replies and 1 member reply shaparage Newbie | Next Rank: 10 Posts Joined 31 Oct 2017 Posted: 2 messages mixture problem. please hep with simple solution Tue Oct 31, 2017 8:23 am Elapsed Time: 00:00 • Lap #[LAPCOUNT] ([LAPTIME]) There are two containers A and B filled with mentha oil with different prices and with volumes 140 and 60 liters respectively. Equal quantities are drawn from both A and B in such a manner that the oil drawn from A is poured in into B and oil drawn from B is poured into A. After doing so, the price per liter becomes equal in both containers. What is the (equal) quantity that was drawn? what is the concept behind this problm ?? Need free GMAT or MBA advice from an expert? Register for Beat The GMAT now and post your question in these forums! Top Member dabral Master | Next Rank: 500 Posts Joined 23 Jan 2009 Posted: 131 messages Followed by: 15 members Thanked: 58 times Wed Nov 01, 2017 9:40 pm Hi shaparage, With these type of problems, the key is to be able to set up the problem and translate it into an equation. One cannot just memorize the approach to these problems. The variations are too many. In this case, we can say that x liters of solution are moved from A to B, and vice versa. Let the price of oil be p1$/liter in container A and p2 $/liter in container B. The total cost of oil in container A will be: (140-x)p1 + (x)p2 Similarly, the cost of oil in container B will be (60-x)p2 + (x)p1. Set the price per liter in the two containers to be equal and you will find that the terms involving p1 and p2 drop out and x turns out to be 42 liters. Cheers, Dabral _________________ Free Video Explanations: 2018 OFFICIAL GUIDE FOR GMAT REVIEW. Thanked by: shaparage GMAT/MBA Expert Matt@VeritasPrep GMAT Instructor Joined 12 Sep 2012 Posted: 2600 messages Followed by: 113 members Thanked: 599 times Target GMAT Score: V51 GMAT Score: 780 Thu Nov 09, 2017 5:55 pm Say that each liter in A costs$a and each liter in B costs $b. Then the price of the barrels is$140a and $60b, respectively. After we switch c liters from each barrel to the other, we've got$(140 - c)*a + cb in one barrel and \$(60 - c)*b + c*a in the other. Since these create an equal price per liter, we have

((140 - c)a + bc)/140 = ((60 - c)b + ac)/60

60 * (140a - ac + bc) = 140 * (60b - bc + ac)

8400a - 60ac + 60bc = 8400b - 140bc + 140ac

8400a - 200ac = 8400b - 200bc

42a - ac = 42b - bc

42a - 42b - ac + bc = 0

(42 - c) * (a - b) = 0

So either c = 42 or a = b. We're told (in the stem) that the prices are different, so a â‰ Â b and c = 42 is our only solution.

Thanked by: shaparage
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GMAT/MBA Expert

Matt@VeritasPrep GMAT Instructor
Joined
12 Sep 2012
Posted:
2600 messages
Followed by:
113 members
Thanked:
599 times
Target GMAT Score:
V51
GMAT Score:
780
Thu Nov 09, 2017 5:59 pm
By the way, that is not a trivial GMAT problem! It takes more than the normal amount of of setup and legwork to sort out, and feels a bit more like an algebra homework problem than anything you'd encounter on this test.

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