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GMAT Average Speed Problems

by Kaplan GMAT on June 29th, 2012
9 comments
Click here to read more articles from Kaplan and to learn more about Kaplan's GMAT classes.
Posted in
  • GMAT Math
  • Problem Solving
  • Speed/Distance
  • Word Problems

Imagine you are driving from Chicago to Los Angeles, and you want to know what your average speed needs to be to reach Los Angeles in a certain number of hours. You would probably start by determining the speed you will be able travel during certain parts of your journey. Since most of the distance will be covered by highway, you might plan to travel most of the distance at 70 miles per hour. However, you will also want to plan for some traffic when you are still in or near Chicago and when you get close to Los Angeles. During these parts of your journey let’s say you can plan to travel at 30 miles per hour.

When calculating the average speed at which you will be traveling, you need to avoid the trap of just averaging these speeds together and planning on an average speed of 50 miles per hour. Because the vast majority of your journey will take place at 70 miles per hour and only a relatively small portion will take place at 30 miles per hour, simply averaging the speeds is not sufficient. You need to account for the difference in the amount of time you will be driving at each speed. Once you do so, your average speed will be much closer to 70 miles per hour than 30 miles per hour.

The same principle will apply when you see average speed questions on the GMAT. Average speed is defined as total distance divided by total time, rather than the average of the speeds. Additionally, the average of the speeds will almost always be offered as an answer choice, so be sure to avoid it.

This can be especially tricky when a problem gives little information other than the two speeds. On test day, you should think strategically and pick a number for the distance, calculate the times using this number, and then plug into the average speed formula described above. Give it a try on the following problem.

Problem:

A canoeist paddled upstream at 10 meters per minute, turned around, and drifted downstream at 15 meters per minute.  If the distance traveled in each direction was the same, and the time spent turning the canoe around was negligible, what was the canoeist’s average speed over the course of the journey, in meters per minute?

(A)  11.5
(B)  12
(C)  12.5
(D)  13
(E)  13.5

Answer

Step 1: Analyze the Question

A canoeist goes one rate in one direction, turns around, and goes back at a different rate. Whenever you deal with one entity that has different rates at different times, set up a chart to track the data. Otherwise, you’ll find yourself in a six-variable, six-equation system that will take a long time to work through. Also, notice that although the distance and time are never mentioned, there are no variables in the answer choices. Whenever variables will cancel out, consider Picking Numbers.

Step 2: State the Task

Our task is to calculate her average speed for the whole journey.

Step 3: Approach Strategically

The formula is this:

Average Speed = Total Distance / Total Time

But we’re seemingly told nothing about time, and the only thing we know about distance is that it is the same in both directions. So what to do? As with almost every problem involving a multistage journey, set up this chart:

Now plug in the data we’re given:

Now we see clearly that we’ll be able to know the time if we know something about the distance. Since we know whatever variable we put in place will cancel out by the time we get to the answer choices, let’s just pick a number for distance—one that will fit neatly with a rate of 10 and a rate of 15. A distance of 30 should work well:

At this point, we can fill in the rest of the chart very straightforwardly. The entire distance is 60. The time taken upstream must be 3, and the time taken downstream must be 2. That makes the entire time 5.

Step 4: Confirm Your Answer

The speed for the entire trip, then, is 60 / 5 = 12. Answer (B).

Reread the question stem, making sure that you didn’t miss anything about the problem.

To all of you strategic thinkers out there, can you spot a way to quickly eliminate 3 of the answer choices without doing any calculations?

If you liked this article, let Kaplan GMAT know by clicking Like.

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9 comments

  • Faruk on July 3rd, 2012 at 4:46 am

    t1 = d/10 and t2 = d/15

    we know total rate = 2d /(t1+t2)
    plugging in the value of t1 and t2 ,we get 12..making chart will take a long time..right ?

    Reply to this comment
  • Brian on July 3rd, 2012 at 10:17 am

    This part of the explanation is misleading: "Because the vast majority of your journey will take place at 70 miles per hour and only a relatively small portion will take place at 30 miles per hour, simply averaging the speeds is not sufficient. You need to account for the difference in the amount of time you will be driving at each speed. Once you do so, your average speed will be much closer to 70 miles per hour than 30 miles per hour."

    This may be true, but the answer depends on the precise distances traveled at each speed, because when you're going slowly, you need more time to travel the same distance (as anyone stuck in a traffic jam can attest), and speed is a function of time.  Let's assume, as a reference point, that the two distances are equal. Because you actually have to spend more time in the car going slowly (30 mph) than you do going quickly (70mph), your average speed should be closer to 30mph than 70mph.  In fact, even in some circumstances where you travel much further at the higher speed than you do at the lower speed, the average speed will still be closer to the lower speed.

    For example, let's say you traveled 200 miles at 100 miles an hour, and then 40 miles at 5 mph.

    It takes you only 2 hours for the speedy part of your journey, and and excruciating 9 hours for the slow part. So your average speed is (distance/time) = 240 miles / 10 hours = 24 mph, which is much closer to the lower speed even though you only traveled at that speed for a small fraction of the total distance traveled. 

    Reply to this comment
    • Brian on July 3rd, 2012 at 10:27 am

      last paragraph: "and an" ;)  

  • Brian on July 3rd, 2012 at 10:29 am

    also, the trip actually took 11 hours total, so the average speed was actually a bit lower than 24 mph.  

    Reply to this comment
    • Brian on July 3rd, 2012 at 10:36 am

      just kidding.  the slow part took 8 hours, not 9 hours.  the average speed is in fact 24 mph.  I wish that you could edit comments on here!  

  • Faruk on July 4th, 2012 at 4:28 am

    Hi Brian,thanks for the explanation..How to eliminate 3 answer choices without calculation?

    Reply to this comment
    • Ngan on July 8th, 2012 at 1:48 am

      I think that we can easily delete 3 choices without calculation if we quickly in our heads calculate that the average speed should be around 12, 5 (since 25/2 =12,5). But we are not sure if it is correct (but we still can keep it as a available option). Now if we check the five answer options, choice A =11,5, B=12, C= 12,5, D=13, E= 13,5. Considering choice A, D, E these speed are either far below or far above our assumed speed (12,5) so we can eliminate them without further thinking. But choice B and C offer the speed close to our assumed speed which is 12,5. And we guess that the answer should be around that speed. That is why we can take a closer look at them and determine which one is correct. I hope you understand my explaination, my english is not the best ^^

    • Brian on July 8th, 2012 at 2:48 pm

      Hi Faruk,

      It's a pretty easy trick when the distances are equal.  If the distance traveled is the same, then the average speed will always be closer to the lower speed than it is to the higher speed, since more time is spent traveling at the lower speed.  Hence we can eliminate C, D and E all at once because none of them is closer to 10 than 15. 

  • somsubhra on August 6th, 2012 at 7:11 pm

    Nice one

    Reply to this comment

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