Finding Your Way Around GMAT Perimeter Questions (Part 6 of 8)
Perimeter questions on the GMAT are a subset of a subset — a small part of the geometry you will inevitably run into on the Quantitative side of the test. Perimeter is the distance around a geometric figure — from Ancient Greek περίμετρος, or “measure around”. And on the GMAT it is just that: the sum of the side lengths of a two-dimensional figure (three dimensional figures have surface area instead). They are in the category of “easy things made hard”. It is not challenging to add up the side lengths of a polygon, even an irregular one, so the GMAT will force you to infer more information to answer the question.
This is a short series of articles showing some of the ways different figures’ information can be used to create perimeter questions.
Last time, I gave you this question about triangles:
In the figure above, triangle CDE is an equilateral triangle with side length 3, AF = 10, EF = 6, and AB = DE. What is the perimeter of the figure?
(A) 45
(B) 36
(C) 29
(D) 24
(E) 16
The answer is (C) 29. How?
The question tells us this much:

From here, we can deduce that:
1. Triangle AEF is a 3:4:5 triangle, with side lengths 6:8:10, respectively.
2. Since AE is 8 and CE is 3, that makes AC = 5.
3. Since AC = 5, triangle ABC is also a 3:4:5 triangle, and BC = 4
We can then have:

10+6+4+(3*3) = 29. Answer choice (A) 45 is the sum of the perimeters of each of the triangles, rather than the perimeter of the figure.
Next time: putting it all together in complex, mixed figures!
Read other articles in this series:
- Finding Your Way Around GMAT Perimeter Questions (Part 1 of 8 )
- Finding Your Way Around GMAT Perimeter Questions (Part 2 of 8 )
- Finding Your Way Around GMAT Perimeter Questions (Part 3 of 8 )
- Finding Your Way Around GMAT Perimeter Questions (Part 4 of 8 )
- Finding Your Way Around GMAT Perimeter Questions (Part 5 of 8 )
- Finding Your Way Around GMAT Perimeter Questions (Part 6 of 8 )



4 comments
YTG on February 13th, 2011 at 8:53 pm
The perimeter is really 37 and not 29. Here is how i calculted it:
Triangle ABC=3+4+5=12
Triangle CDE=3*3=9
Side EF=6
Side AF=10
Perimeter =12+9+6+10=37
bmg on February 14th, 2011 at 12:10 am
AE is not in the perimeter.
YTG on February 14th, 2011 at 3:43 am
Yes, thank you for your comment. Now I have seen Where i got it wrong.
subhakam on February 23rd, 2013 at 1:51 pm
Jim - i did not understand what the perimeter of the figure includes. When i calculated, i fell in the trap of adding up all the triangles together (45) which is not the case. Can you explain please what components you took in order to calculate the perimeter? Why did not calculate or add in the lengths of AB and AC ?
Thanks