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Math Question

This topic has 4 member replies
kashewman Newbie | Next Rank: 10 Posts Default Avatar
Joined
14 Aug 2006
Posted:
8 messages

Math Question

Post Sun Sep 10, 2006 10:58 am
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    I had one question that I don't seem to understand.

    Algebra: [(1/5)^m] * [(1/4)^18] = 1/[2(10)^35]
    what is m?

    Any insight would be appreciated, thanks.

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    kashewman Newbie | Next Rank: 10 Posts Default Avatar
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    Post Sun Sep 10, 2006 11:00 am
    Does anyone have a good formula for mixture problems? Thanks.

    aim-wsc Legendary Member
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    Post Sun Sep 10, 2006 11:48 am
    ...err can you make some things clear?

    like: 2(10)^35 did you mean [(2(10))^35]=20^35
    or 2 X (10)^35

    OK i presume its latter one.

    Its a tricky one & i must confess i had to used my instincts

    before i explain the answer, you must understand the following rule

    given n>m
    then
    (a^m) X (b^n) = ((aXb)^m) X (b^(n-m))

    eg. (5^4) X (3^6) = ((5X3)^4) X (3^2)
    = (15 ^4) X 9


    OK back to problem.
    LHS:
    (1/5)^m * (1/4)^18
    this can be also wirtten as
    Arrow (1/5)^m * (1/2)^36

    RHS:
    1/[2 X 10^35]= 1/[2 X (2X5)^35)]
    Arrow =1/[(2^36) X (5^35)]


    ANSWER:
    therefore
    m=35

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    Post Sun Sep 10, 2006 7:34 pm
    kashewman wrote:
    Does anyone have a good formula for mixture problems? Thanks.
    Check out page 48 of my GMAT Flashcards: http://www.beatthegmat.com/viewtopic.php?t=32

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    abby_g Junior | Next Rank: 30 Posts Default Avatar
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    Post Sat Sep 30, 2006 2:06 am
    The answer is : m = 35

    RHS: 1/2(10)^35 = (1/5^35 )* (1/2^36)
    = (1/5^35) * (1/4^18)

    equate on both sides and woyla you get m = 35. Correct?

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