Linear equation

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crackgmat007
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Topic: Linear equation
PostSat Sep 26, 2009 10:23 am Reply with quote
Can someone explain pls?
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akhilkathuria
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Test Date: 27 October 2009
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PostSat Sep 26, 2009 11:06 am Reply with quote
Sure buddy.

root of (X^2 - 6X +9) = (x-3)^2
now every expression under the root is positive.
So root of (x-3)^2 = x-3 (have to take positive)

now add x-3 + root of (2-x) + x-3

give you the answer 2x-6+ root of(2-x)

please let me know

thanks,
Akhil
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crackgmat007
GMAT Destroyer!



Joined: 20 Feb 2009
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Thanks given: 63
Thanked 10 times in 10 posts
PostSat Sep 26, 2009 11:30 am Reply with quote
akhilkathuria wrote:
Sure buddy.

root of (X^2 - 6X +9) = (x-3)^2
now every expression under the root is positive.
So root of (x-3)^2 = x-3 (have to take positive)

now add x-3 + root of (2-x) + x-3

give you the answer 2x-6+ root of(2-x)

please let me know

thanks,
Akhil
Even I got B. But OA is A
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