Linear equation

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crackgmat007
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Topic: Linear equation

Sat Sep 26, 2009 11:23 am

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Can someone explain pls?

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akhilkathuria
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Sat Sep 26, 2009 12:06 pm

Sure buddy. root of (X^2 - 6X +9) = (x-3)^2 now every expression under the root is positive. So root of (x-3)^2 = x-3 (have to take positive) now add x-3 + root of (2-x) + x-3 give you the answer 2x-6+ root of(2-x) please let me know thanks, Akhil

crackgmat007
GMAT Destroyer!

Joined: 20 Feb 2009
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Target GMAT Score: 700+
GMAT Score: 690

Sat Sep 26, 2009 12:30 pm

akhilkathuria wrote: Sure buddy. root of (X^2 - 6X +9) = (x-3)^2 now every expression under the root is positive. So root of (x-3)^2 = x-3 (have to take positive) now add x-3 + root of (2-x) + x-3 give you the answer 2x-6+ root of(2-x) please let me know thanks, Akhil Even I got B. But OA is A