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IRQ2 - How to solve

This topic has 1 member reply
prashanth.guru Newbie | Next Rank: 10 Posts Default Avatar
Joined
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Posted:
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IRQ2 - How to solve

Post Thu Aug 08, 2013 11:43 pm
Please let me how to solve the question in the attached image to arrive at the ans marked in the squares of each column

ttp://postimg.org/image/65hfmcvp3/" target="_blank">

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Post Wed Aug 21, 2013 12:27 am
prashanth.guru wrote:
Please let me how to solve the question in the attached image to arrive at the ans marked in the squares of each column

ttp://postimg.org/image/65hfmcvp3/" target="_blank">
If they ask for an approximate value, we can just ballpark our answers! We can safely take π to be 3 so that 4πr^2 is 12r^2. Rate is $92 per square meter, close to 90, so the cost is close to 12r^2 times 90, which is 1080r^2.

A 5.50 meter circumference means the radius is 5.5/ (2 π), slightly less than 1 and so is r^2. Therefore, 1080r^2 would be around $1000 or less, pick A.

A 7.85 meter circumference means the radius is 7.85/ (2 π), around 1.3 and so r^2 is around 1.7. Therefore, 1080r^2 would be something near to 2000 and less. Pick C

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