Q.Is x > y?
(1) x ^ 1/2 > y
(2) x^3 > y
Q.Is X > Y?
(!) x^2 >y
(2) x^ 1/2 < y
For questions like these, what are the suitable numbers that we need to test for . I take positive and negative fractions like x = 1/4, y = 1/3etc. Sometimes I get stuck due to these numbers only.
Please suggest any approach to take on these inequality questions.
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Inequality
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prachi18oct
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GMATGuruNY
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For this problem, I posted two approaches here:prachi18oct wrote:Q.Is x > y?
(1) x ^ 1/2 > y
(2) x^3 > y
https://www.beatthegmat.com/x-y-t280459.html
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Test a value for x whose square and root can be calculated easily.prachi18oct wrote:
Q.Is X > Y?
(!) x^2 > y
(2) x^ 1/2 < y
Let x=4.
The statements become:
Statement 1: 16 > y
Statement 2: 2 < y
Both statements are satisfied if y=3, in which case x>y.
Both statements are satisfied if y=5, in which case x<y.
INSUFFICIENT.
The correct answer is E.
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Matt@VeritasPrep
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There are lots of ways to see that neither statement alone is sufficient. (Number picking is probably the easiest. For instance, in the first one, x could be negative and y positive, or vice versa. In the second, we could have y = 4 and √x = 1, or we could have y = 3 and √x = 2.)Is x > y?
S1:: x² > y
S2:: y > √x
Taking the two together, we have
x² > y > √x
This makes it easier to test numbers. We could have √x = 2 and y = 3, in which case x = 4 and x > y. But we could also have √x = 2 and y = 15, in which case x = 4 (as before) but now y > x.
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Brent@GMATPrepNow
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Aside: Once we combine the statements, we get: √x < y < x²
If we ignore the y, we see that √x < x²
When it comes to the squares and square roots of positive numbers, there are three possible cases:
case a: If 0 < k < 1, then √k > k²
case b: If k = 1, then √k = k²
case c: If 1 < k, then √k < k²
Since the combined statements tell us that √x < x², we can conclude that 1 < x
When we test certain values of x that are greater than 1 (as others have done above), we see that the combined statements are still insufficient.
Cheers,
Brent
If we ignore the y, we see that √x < x²
When it comes to the squares and square roots of positive numbers, there are three possible cases:
case a: If 0 < k < 1, then √k > k²
case b: If k = 1, then √k = k²
case c: If 1 < k, then √k < k²
Since the combined statements tell us that √x < x², we can conclude that 1 < x
When we test certain values of x that are greater than 1 (as others have done above), we see that the combined statements are still insufficient.
Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
