2. If x and y are nonzero integers,
is ((x^-1) + (y^-1))^-1 > [(x^-1)(y^-1)]^-1 ?
(1) x = 2 y
(2) x + y > 0
Source: Some yahoo group
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Inequality Question
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Cybermusings
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I think it is A
It boils down to xy/(x+y) > xy
1) x=2y ---> both x and y have same sign
xy is always (+)ive
xy is always > than xy/(x+y) for (-)ive as well as (+)ive values of x and y
take x=-4 and y = -1
or take x=4 and y=1
2) doesn't provide info on xy. Insuff
It boils down to xy/(x+y) > xy
1) x=2y ---> both x and y have same sign
xy is always (+)ive
xy is always > than xy/(x+y) for (-)ive as well as (+)ive values of x and y
take x=-4 and y = -1
or take x=4 and y=1
2) doesn't provide info on xy. Insuff
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priya_rai1
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gmat doctor
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axisymmetric
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