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In the rectangular coordinate (OG16)

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boomgoesthegmat Senior | Next Rank: 100 Posts Default Avatar
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In the rectangular coordinate (OG16)

Post Thu May 19, 2016 3:48 pm
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    ttp://postimg.org/image/wm6pco681/" target="_blank">

    In the rectangular coordinate system above, if point R (not shown) lies on the positive y-axis and the area of triangle ORP is 12, what is the y-coordinate of point R?

    A) 3
    B) 6
    C) 9
    D) 12
    E) 24

    OA: B

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    Post Thu May 19, 2016 4:53 pm
    Hi boomgoesthegmat,

    From the diagram, we know that the base of triangle ORP = 4. We also know that it's area = 12, so we can combine those two pieces of information to find the height of the triangle (and by extension, the Y co-ordinate of point R).

    Area = (1/2)(base)(height)

    12 = (1/2)(4)(height)
    12 = 2(height)
    6 = height

    Final Answer: B

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    Post Tue Dec 12, 2017 6:32 am
    boomgoesthegmat wrote:
    ttp://postimg.org/image/wm6pco681/" target="_blank">

    In the rectangular coordinate system above, if point R (not shown) lies on the positive y-axis and the area of triangle ORP is 12, what is the y-coordinate of point R?

    A) 3
    B) 6
    C) 9
    D) 12
    E) 24
    '
    We are given that point P lies at (4,0) and point R lies on the y-axis. Thus, we see that we have a right triangle with one vertex at point P, another at coordinate (0,0), and the other at point R. Thus, the base of the triangle is 4, and the height is the y-coordinate of point R.

    Since we know the area of the triangle is 12, we can create the following equation in which y = the y-coordinate of point R.

    area = (base x height)/2

    12 = 4y/2

    24 = 4y

    6 = y

    Answer: B

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