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In the equation above, k is a constant.

This topic has 1 expert reply and 0 member replies
boomgoesthegmat Senior | Next Rank: 100 Posts Default Avatar
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In the equation above, k is a constant.

Post Wed May 04, 2016 4:30 am
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    y = kx + 3

    In the equation above, k is a constant. If y = 17 when x = 2, what is the value of y when x = 4 ?

    A) 34
    B) 31
    C) 14
    D) 11
    E) 7

    OA: B

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    Post Wed May 04, 2016 5:54 am
    boomgoesthegmat wrote:
    y = kx + 3

    In the equation above, k is a constant. If y = 17 when x = 2, what is the value of y when x = 4 ?

    A) 34
    B) 31
    C) 14
    D) 11
    E) 7

    OA: B
    Let's find the value of k
    We're told that y = 17 when x = 2 is one solution to the equation y = kx + 3
    This means that 17 = k(2) + 3
    Simplify: 17 = 2k + 3
    So, 14 = 2k
    We get: k = 7

    So, the equation is y = 7x + 3
    When x = 4, we get y = 7(4) + 3
    So, y = 28 + 3 = 31

    Answer: B

    Cheers,
    Brent

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