In one alloy there is 12% chromium while in another alloy it is 8%. 15 kg of the first alloy was melted together with 35 kg of the second one to form a third alloy. Find the percentage of chromium in the new alloy.
(A) 8.8%
(B) 9%
(C) 9.2%
(D) 8.6%
(E) 8.4%
The OA is C.
I'm confused with this PS question. Experts, any suggestion about how to solve it? Thanks in advance.
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In one alloy there is 12% chromium while in another...
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BTGmoderatorLU
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15 kg 12% chromium is combined with 35 kg 8% chromium to form a 50 kg alloy.LUANDATO wrote:In one alloy there is 12% chromium while in another alloy it is 8%. 15 kg of the first alloy was melted together with 35 kg of the second one to form a third alloy. Find the percentage of chromium in the new alloy.
(A) 8.8%
(B) 9%
(C) 9.2%
(D) 8.6%
(E) 8.4%
Average percent chromium for the entire 50 kg = (15*12 + 35*8)/50 = 460/50 = 46/5 = 9.2.
The correct answer is C.
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The percentage of chromium in the new alloy is:BTGmoderatorLU wrote:In one alloy there is 12% chromium while in another alloy it is 8%. 15 kg of the first alloy was melted together with 35 kg of the second one to form a third alloy. Find the percentage of chromium in the new alloy.
(A) 8.8%
(B) 9%
(C) 9.2%
(D) 8.6%
(E) 8.4%
The OA is C.
I'm confused with this PS question. Experts, any suggestion about how to solve it? Thanks in advance.
(0.12 x 15 + 0.08 x 35)/(15 + 35) x 100
(1.8 + 2.8)/50 x 100
4.6 x 2
9.2
Answer: C
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