If x and y are positive integers such that x^2+y^3 is a prime number less than 18, what is the value of y ?
1. x^2+y^2 is a prime number
2. x^2-y^2 is a prime number
OA : E
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If x and y are positive integers such that x^2+y^3 is a
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Since x²+y³ is a prime number less than 18, there are limited options for x² and y³:If x and y are positive integers such that x²+y³ is a prime number less than 18, what is the value of y?
1. x²+y² is a prime number
2. x²-y² is a prime number
x² = 1, 4, 9, or 16.
y³ = 1 or 8.
Options for their sum:
x²+y³ =1+1 = 2
x²+y³ = 4+1 = 5
x²+y³ = 9+8 = 17
x²+y³ = 16+1 = 17.
Both statements are satisfied if x²+y³ = 4+1 = 5, in which case x=2 and y=1.
Both statements are satisfied if x²+y³ = 9+8 = 17, in which case x=3 and y=2.
Since y can be different values, the two statements combined are INSUFFICIENT.
The correct answer is E.
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Hi Mitch,GMATGuruNY wrote:Since x²+y³ is a prime number less than 18, there are limited options for x² and y³:If x and y are positive integers such that x²+y³ is a prime number less than 18, what is the value of y?
1. x²+y² is a prime number
2. x²-y² is a prime number
x² = 1, 4, 9, or 16.
y³ = 1 or 8.
Options for their sum:
x²+y³ =1+1 = 2
x²+y³ = 4+1 = 5
x²+y³ = 9+8 = 17
x²+y³ = 16+1 = 17.
Both statements are satisfied if x²+y³ = 4+1 = 5, in which case x=2 and y=1.
Both statements are satisfied if x²+y³ = 9+8 = 17, in which case x=3 and y=2.
Since y can be different values, the two statements combined are INSUFFICIENT.
The correct answer is E.
Please can you explain Statement 2..?
Many thanks,
Mallika
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This is a pretty time-consuming question.If x and y are positive integers such that x²+y³ is a prime number less than 18, what is the value of y?
1. x²+y² is a prime number
2. x²-y² is a prime number
Target question: What is the value of n?
Given: x and y are positive integers such that x²+y³ is a prime number less than 18
Since x²+y³ must be less than 18, the values of x and y are quite restricted.
x can equal 1, 2, 3 or 4
y can equal 1 or 2
Let's first check all 8 possible configurations of x²+y³ to see which ones are prime:
x = 1 and y = 1: x²+y³ = 1 + 1 = 2 (PRIME)
x = 1 and y = 2: x²+y³ = 1 + 8 = 9 (NOT prime)
x = 2 and y = 1: x²+y³ = 4 + 1 = 5 (PRIME)
x = 2 and y = 2: x²+y³ = 4 + 8 = 12 (NOT prime)
x = 3 and y = 1: x²+y³ = 9 + 1 = 2 (NOT prime)
x = 3 and y = 2: x²+y³ = 9 + 8 = 17 (PRIME)
x = 4 and y = 1: x²+y³ = 16 + 8 = 17 (PRIME)
x = 4 and y = 2: x²+y³ = 16 + 8 = 24 (NOT prime and too big)
So, there are 4 possible cases where x²+y³ is prime. They are:
case a) x = 1 and y = 1
case b) x = 2 and y = 1
case c) x = 3 and y = 2
case d) x = 4 and y = 1
Now check the statements:
Statement 1: x²+y² is a prime number
Let's test all 4 possible cases:
case a) x = 1 and y = 1: Here x²+y² = 1+1 = 2 (PRIME). In this case y = 1
case b) x = 2 and y = 1: Here x²+y² = 4+1 = 5 (PRIME). In this case y = 1
case c) x = 3 and y = 2: Here x²+y² = 9+4 = 13 (PRIME). In this case y = 2
case d) x = 4 and y = 1: Here x²+y² = 16+1 = 17 (PRIME). In this case y = 1
Since y can equal 1 or 2, statement 1 is NOT SUFFICIENT
Statement 2: x²-y² is a prime number
Let's test all 4 possible cases:
case a) x = 1 and y = 1: Here x²-y² = 1-1 = 0 (NOT prime). So, case a is not possible.
case b) x = 2 and y = 1: Here x²-y² = 4-1 = 3 (PRIME). In this case y = 1
case c) x = 3 and y = 2: Here x²-y² = 9-4 = 5 (PRIME). In this case y = 2
case d) x = 4 and y = 1: Here x²-y² = 16-1 = 15 (NOT prime). So, case d is not possible.
Since y can equal 1 or 2, statement 2 is NOT SUFFICIENT
Statements 1 and 2 combined
Statement 1 tells us that cases a, b, c and d are all possible
Statement 2 tells us that cases b and c are possible
So, when the statements are combined, we can conclude that cases b and c are possible.
Case b tells us that y = 1
Case c tells us that y = 2
Since we cannot answer the target question with certainty, the combined statements are NOT SUFFICIENT
Answer = E
Cheers,
Brent