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If x and y are positive integers, is (x/y)^z > 1 ?

This topic has 1 expert reply and 0 member replies

If x and y are positive integers, is (x/y)^z > 1 ?

Post Wed Sep 20, 2017 8:04 am
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    If x and y are positive integers, is (x/y)^z > 1 ?

    (1) x - y = -5
    (2) z ≠ 0

    The OA is E.

    Both statements are not sufficient? Why? How can I conclude that the correct option is E?

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    Post Wed Sep 20, 2017 9:28 pm
    Vincen wrote:
    If x and y are positive integers, is (x/y)^z > 1 ?

    (1) x - y = -5
    (2) z ≠ 0

    The OA is E.

    Both statements are not sufficient? Why? How can I conclude that the correct option is E?
    Statement 1: x - y = -5

    => A positive integer (y) is subtracted from a positive integer (x), leaving a negative integer (-5); thus, y > x.

    Thus, x/y < 1

    Case 1: If z is negative. Say z = -1, x = 1 and y = 6, then (x/y)^z = (1/6)^(-1) = 6 > 1. The asnwer is Yes.
    Case 2: If z is positive. Say z = 1, x = 1 and y = 6, then (x/y)^z = (1/6)^(1) = 1/6 < 1. The asnwer is No.

    No unique answer. Insufficient.

    Statement 2: z ≠ 0

    Both the cases discussed above are applicable here too. Insufficient.

    Statement 1 & 2:

    As stated, both the cases discussed above are applicable here too. Insufficient.

    The correct answer: E

    Hope this helps!

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    Thanked by: Vincen

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