• Award-winning private GMAT tutoring
Register now and save up to \$200

Available with Beat the GMAT members only code

• Free Veritas GMAT Class
Experience Lesson 1 Live Free

Available with Beat the GMAT members only code

• Free Trial & Practice Exam
BEAT THE GMAT EXCLUSIVE

Available with Beat the GMAT members only code

• Get 300+ Practice Questions

Available with Beat the GMAT members only code

• 1 Hour Free
BEAT THE GMAT EXCLUSIVE

Available with Beat the GMAT members only code

• Magoosh
Study with Magoosh GMAT prep

Available with Beat the GMAT members only code

• Free Practice Test & Review
How would you score if you took the GMAT

Available with Beat the GMAT members only code

• 5-Day Free Trial
5-day free, full-access trial TTP Quant

Available with Beat the GMAT members only code

• 5 Day FREE Trial
Study Smarter, Not Harder

Available with Beat the GMAT members only code

## If the sum of the reciprocals of two consecutive

tagged by: Brent@GMATPrepNow

This topic has 2 expert replies and 1 member reply

### Top Member

Vincen Master | Next Rank: 500 Posts
Joined
07 Sep 2017
Posted:
363 messages
Thanked:
5 times

#### If the sum of the reciprocals of two consecutive

Sun Sep 24, 2017 6:41 am
Elapsed Time: 00:00
• Lap #[LAPCOUNT] ([LAPTIME])
If the sum of the reciprocals of two consecutive odd integers is 12/35 then the greater of the two integers is

A) 3
B) 5
C) 7
D) 9
E) 11

The OA is C.

Should I solve the equation 1/(2k+1) + 1/(2k+3) = 12/35? Or there is another way to solve it?

Need free GMAT or MBA advice from an expert? Register for Beat The GMAT now and post your question in these forums!

### Top Member

pannalal Junior | Next Rank: 30 Posts
Joined
20 Sep 2017
Posted:
20 messages
Thanked:
2 times
Sun Sep 24, 2017 6:58 am
Let us assume that two consecutive odd integers are a and b where b = a+2. Then, sum of their reciprocal is (a+b)/ab. We have been given that sum of two consecutive odd integers is 12/35.

As GCD of two consecutive integers is always 1, sum of these two is 12 and multiplication of these two integers is 35.

Obviously, these two odd integers are 5 and 7.

Thus, larger integer is 7. So, answer is C.

Last edited by pannalal on Sun Sep 24, 2017 7:22 am; edited 1 time in total

### GMAT/MBA Expert

Brent@GMATPrepNow GMAT Instructor
Joined
08 Dec 2008
Posted:
10763 messages
Followed by:
1212 members
Thanked:
5144 times
GMAT Score:
770
Sun Sep 24, 2017 7:01 am
Vincen wrote:
If the sum of the reciprocals of two consecutive odd integers is 12/35 then the greater of the two integers is

A) 3
B) 5
C) 7
D) 9
E) 11
Since the denominator of the sum is 35, and since 35 equals the product of 5 and 7 (two consecutive odd integers), let's start by testing whether 5 and 7 are the integers in question.

So, the RECIPROCALS are 1/5 and 1/7
1/5 + 1/7 = 7/35 + 5/35
= 12/35
Voila!!

So, the odd integers are 5 and 7
The greater of the two integers is 7

Cheers,
Brent

_________________
Brent Hanneson – Founder of GMATPrepNow.com
Use our video course along with

Check out the online reviews of our course
Come see all of our free resources

GMAT Prep Now's comprehensive video course can be used in conjunction with Beat The GMAT’s FREE 60-Day Study Guide and reach your target score in 2 months!

### GMAT/MBA Expert

Rich.C@EMPOWERgmat.com Elite Legendary Member
Joined
23 Jun 2013
Posted:
8703 messages
Followed by:
460 members
Thanked:
2732 times
GMAT Score:
800
Sun Sep 24, 2017 10:34 am
Hi Vincen,

We're told that the sum of the reciprocals of two CONSECUTIVE ODD integers is 12/35. We're asked for the GREATER of the two integers. This question can be solved by TESTing THE ANSWERS.

IF.... the values are 3 and 5....
then the sum of the reciprocals is 1/3 + 1/5 = 5/15 + 3/15 = 8/15
This is clearly not the correct answer, but the denominator ends in a '5', so it's likely that 12/35 will ALSO include a 5...

IF.... the values are 5 and 7....
then the sum of the reciprocals is 1/5 + 1/7 = 7/35 + 5/35 = 12/35
This is an exact match for what we were told, so this MUST be the answer.

GMAT assassins aren't born, they're made,
Rich

_________________
Contact Rich at Rich.C@empowergmat.com

### Best Conversation Starters

1 Vincen 180 topics
2 lheiannie07 65 topics
3 Roland2rule 49 topics
4 ardz24 40 topics
5 LUANDATO 16 topics
See More Top Beat The GMAT Members...

### Most Active Experts

1 Brent@GMATPrepNow

GMAT Prep Now Teacher

146 posts
2 Rich.C@EMPOWERgma...

EMPOWERgmat

103 posts
3 GMATGuruNY

The Princeton Review Teacher

100 posts
4 EconomistGMATTutor

The Economist GMAT Tutor

92 posts
5 Jay@ManhattanReview

Manhattan Review

79 posts
See More Top Beat The GMAT Experts