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If the average (arithmetic mean) of

This topic has 2 expert replies and 0 member replies
boomgoesthegmat Senior | Next Rank: 100 Posts Default Avatar
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If the average (arithmetic mean) of

Post Thu Apr 28, 2016 1:41 pm
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N + 1) is 18, then N =

    A) 19
    B) 20
    C) 21
    D) 22
    E) 29

    C

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    Post Thu Apr 28, 2016 1:45 pm
    boomgoesthegmat wrote:
    If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N + 1) is 18, then N =

    A) 19
    B) 20
    C) 21
    D) 22
    E) 29
    If the average of the four numbers is 18, then we know that [3 + 15 + 32 + (N+1)]/4 = 18
    Multiply both sides by 4 to get: 3 + 15 + 32 + (N+1) = 72
    Simplify: 51 + N = 72
    Solve: N = 21
    Answer: C


    Related Resource
    The following video covers the concepts/strategies that are useful for answering this question:
    - Mean, median and mode: https://www.gmatprepnow.com/module/gmat-statistics/video/800

    Cheers,
    Brent

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    Post Thu Apr 28, 2016 2:08 pm
    (3 + 15 + 32 + n + 1) / 4 = 18

    51 + n = 4 * 18

    n = 72 - 51

    n = 21

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