If k and t are integers...

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BlindVision
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Topic: If k and t are integers...
PostThu Jul 02, 2009 5:35 pm

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If k and t are integers and k^2 - t^2 is an odd integer, which of the following must be an even integer?

I. k + t +2

II. k^2 + 2kt + t^2

III. k^2 + t^2

A) None

B) I only

C) II only

D) III only

E) I, II, and III

OA=A

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shibal
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PostThu Jul 02, 2009 5:42 pm

pick numbers...since k^2 - t^2 is odd, k must be odd and t even...
thus, for k choose 3 and t choose 2... plug in and u'll see that it's A
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PostThu Jul 02, 2009 5:55 pm

for k^2 - t^2 to be odd: one of them needs to be odd and one of them needs to be even.

O^2 - E^2 = O

it works the same way when you add: E + O = O, with or without squaring the numbers.

I) O + E = O

II) O + E + E = O

III) O^2 + E^2 = O

therefore all three of them are odd. so it is (A)


Last edited by ssmiles08 on Thu Jul 02, 2009 7:58 pm; edited 1 time in total
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PostThu Jul 02, 2009 7:38 pm

plugin number k=5,t=4
A

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PostThu Jul 02, 2009 7:44 pm

Hey Ssmiles, I think you meant O + E + E = O in example II. Very Happy

Thank you Ssmiles & shibal, I see the approach now!

Thanks 2HB for the help.

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PostThu Jul 02, 2009 8:00 pm

BlindVision wrote:
Hey Ssmiles, I think you meant O + E + E = O in example II. Very Happy

Thank you Ssmiles & shibal, I see the approach now!

Thanks 2HB for the help.
yes...thank you for pointing it out...i seem to typo myself about a 1000 times every post.
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PostFri Jul 03, 2009 12:36 am

Plug in consecutive numbers for 'k' and 't' - will help work the question out faster.
For eg: k=6 , t= 5 ; k=7 , t=8

Regards,
N
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