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If a*b is an even integer, is b a multiple of 2?

This topic has 1 expert reply and 0 member replies

If a*b is an even integer, is b a multiple of 2?

Post Wed Sep 20, 2017 3:00 am
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    If a*b is an even integer, is b a multiple of 2?

    (1) a is not a multiple of 2.
    (2) b is product of two consecutive integers.

    I'm quite confused about the statements, isn't Option D the right answer?

    OA B

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    Post Wed Sep 20, 2017 3:21 am
    lheiannie07 wrote:
    If a*b is an even integer, is b a multiple of 2?

    (1) a is not a multiple of 2.
    (2) b is product of two consecutive integers.

    I'm quite confused about the statements, isn't Option D the right answer?

    OA B
    Statement 1 itself is not sufficient.

    Case 1: a = 2/3 and b = 3, then a*b = 2/3*3 = 2; thus, b is NOT a multiple of 2. The answer is No.

    The question does not say that a and b are integers. They are numbers.

    Case 2: a = 3 and b = 2, then a*b = 3*2 = 6 (even); thus, b is a multiple of 2. The answer is Yes.

    Insufficient.

    The correct answer: B

    Hope this helps!

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