How many ways could three people...

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How many ways could three people...

by swerve » Wed Jan 17, 2018 11:58 am
How many ways could three people sit at a table with five seats in which two of the five seats will remain empty?

A) 8
B) 12
C) 60
D) 118
E) 120

The OA is C.

Please, can any expert explain this PS question for me? I tried to solve it but I can't get the correct answer. I need your help. Thanks.

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by GMATGuruNY » Wed Jan 17, 2018 12:12 pm
swerve wrote:How many ways could three people sit at a table with five seats in which two of the five seats will remain empty?

A) 8
B) 12
C) 60
D) 118
E) 120
Let the 3 people be A, B and C.
Number of options for A = 5. (Any of the 5 seats.)
Number of options for B = 4. (Any of the 4 remaining seats.)
Number of options for C = 3. (Any of the 3 remaining seats.)
To combine these options, we multiply:
5*4*3 = 60.

The correct answer is C.
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by DrMaths » Wed Jan 17, 2018 12:16 pm
Out of 5 positions, 1 to 5, the 2 empty chairs can be arranged, for example, at positions 1 and 2, written as 12 below.

Using this notation, here is a list of the empty seat positions: 12,13,14,15,23,24,25,34,35,45 = 10 combinations.

That answer is not provided in the question.

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by GMATGuruNY » Wed Jan 17, 2018 12:25 pm
DrMaths wrote:Out of 5 positions, 1 to 5, the 2 empty chairs can be arranged, for example, at positions 1 and 2, written as 12 below.

Using this notation, here is a list of the empty seat positions: 12,13,14,15,23,24,25,34,35,45 = 10 combinations.

That answer is not provided in the question.
The result in blue must be multiplied by the number of ways the 3 people can be arranged in the occupied seats (3!):
10 * 3! = 60.

We could also proceed as follows:

From the 5 seats, the number of ways to choose 3 to be occupied = 5C3 = (5*4*3)/(3*2*1) = 10.
Within the occupied seats, the number of ways to arrange the 3 people = 3! = 6.
To combine the options above, we multiply:
10*6 = 60.
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by DrMaths » Wed Jan 17, 2018 2:21 pm
Yes GMATGURUNY,
Thank you. I concur and see the former undersight.
The 3! comes from ABC, ACB, BAC, BCA, CAB, CBA arrangements of the three people, Arty, Beth and Charlie!
10 x 6 = 60.