How many five- digit numbers can be formed using digits 0,1,2,3,4,5, Which are divisible by 3, without any of the digits repeating?
A. 15
B. 96
C. 120
D. 181
E. 216
[spoiler]OA:E[/spoiler]
How many five digit numbers can be formed using digits 0,1,2
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- Anaira Mitch
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If the sum of the digits of integer N is a multiple of 3, then N itself is a multiple of 3.Anaira Mitch wrote:How many five- digit numbers can be formed using digits 0,1,2,3,4,5, Which are divisible by 3, without any of the digits repeating?
A. 15
B. 96
C. 120
D. 181
E. 216
Adding 5 of the digits above, there are 2 ways to get a sum that is a multiple of 3 if no digit is repeated:
1+2+3+4+5 = 15 and 0+1+2+4+5 = 12.
Number of ways to arrange 1,2,3,4,5 = 5! = 120.
Number of 5-digit integers composed of 0,1,2,4,5:
Ten-thousands digit can be 1,2,4,5 = 4 choices.
Number of ways to arrange the remaining 4 digits = 4! = 24.
Combining our choices for the digits, we get:
Number of possible integers = 4*24 = 96.
Thus, total possible integers = 120+96 = 216.
The correct answer is E.
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
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