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how many days would it take machine X alone to produce 2w

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netigen GMAT Destroyer! Default Avatar
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how many days would it take machine X alone to produce 2w Post Fri May 30, 2008 11:44 am
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    Running at their respective constant rates, machine X takes 2 days longer to produce w widgets than machine Y. At these rates, if the two machines together produce (5/4)w widgets in 3 days, how many days would it take machine X alone to produce 2w widgets?
    A. 4
    B. 6
    C. 8
    D. 10
    E. 12

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    aatech Really wants to Beat The GMAT! Default Avatar
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    Post Fri May 30, 2008 12:07 pm
    ANS 12..

    Suppose machine Y produces w widgets in d days

    so, X produces same in d+2 days

    In 1 day Y produces w/d and X produces w/(d+2) widgets

    Working together they will produce w/d + w/(d+2) = [2w(d+1)]/[d(d+2)] widgets in 1 day

    in 3 days they produce 3*[2w(d+1)]/[d(d+2)] = 5w/4

    Solve to get d =4

    x produces w widgets in 4+2 = 6 days

    so, 2w widgets will be produces in 12 days

    OA???

    netigen GMAT Destroyer! Default Avatar
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    Post Fri May 30, 2008 12:21 pm
    OA is E

    niraj_a GMAT Destroyer! Default Avatar
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    Post Mon Dec 15, 2008 7:42 pm
    i realize this is an old post but could someone show me the actual calculation that goes from this step -

    in 3 days they produce 3*[2w(d+1)]/[d(d+2)] = 5w/4

    to this step -

    Solve to get d =4

    i seem to be making a simple error somewhere...

    parallel_chase GMAT Titan Default Avatar
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    Post Tue Dec 16, 2008 4:42 am
    Let the no. of days that Y takes is d

    then no. of days that X takes will be d+2

    X's rate = w/(d+2)
    Y's rate = w/d

    [w/d + w/(d+2)] * 3 = 5w/4

    (w(d+2) + wd) /d(d+2) = 5w/12

    wd + 2w + wd = 5wd(d+2)/12

    24w(d+1) = 5wd(d+2)

    24(d+1) = 5d(d+2)

    24d + 24 = 5d^2 + 10d

    5d^2 -14d - 24 = 0

    5d^2 - 20d + 6d -24 = 0

    (5d+6) ( d-4) = 0

    d=-6/5 or 4

    time cannot be negative, hence d=4

    X produces w in d+2 = 4+2

    2w will be produced in 6+6 = 12 days

    Hope this helps.

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    gmatusa2010 Really wants to Beat The GMAT! Default Avatar
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    Post Wed Dec 22, 2010 3:37 am
    anybody know the source of this problem? or think its realistic gmat problem?

    GMAT/MBA Expert

    Post Wed Dec 22, 2010 6:27 am
    netigen wrote:
    Running at their respective constant rates, machine X takes 2 days longer to produce w widgets than machine Y. At these rates, if the two machines together produce (5/4)w widgets in 3 days, how many days would it take machine X alone to produce 2w widgets?
    A. 4
    B. 6
    C. 8
    D. 10
    E. 12
    This question is from GMATPrep. An efficient way to solve this problem is to plug in the answer choices.

    Let w=12.
    In 3 days, X and Y need to produce 5/4*w = 5/4*12 = 15 widgets.
    The answer choices represent the time for X to produce 2w=24 widgets.

    Answer choice C: 8 days for X to produce 24 widgets
    Thus, X produces 12 widgets in 4 days.
    Since X takes 2 days longer, Y produces 12 widgets in 4-2=2 days.
    Rate for X = w/t = 12/4 = 3/day.
    Rate for Y = w/t = 12/2 = 6/day.
    Combined rate for X+Y = 3+6 = 9/day .
    Work completed in 3 days = r*t = 9*3 = 27 widgets.
    Incorrect: almost DOUBLE the required number of widgets (15) is being produced.
    Thus, X and Y need to work MUCH MORE SLOWLY, implying that the time for X to produce 24 widgets must be MUCH LONGER.

    Answer choice E: 12 days for X to produce 24 widgets
    Thus, X produces 12 widgets in 6 days.
    Since X takes 2 days longer, Y produces 12 widgets in 6-2=4 days.
    Rate for X = w/t = 12/6 = 2/day.
    Rate for Y = w/t = 12/4 = 3/day.
    Combined rate for X+Y = 2+3 = 5/day.
    Work completed in 3 days = r*t = 5*3 = 15 widgets. Success!

    The correct answer is E.

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    Last edited by GMATGuruNY on Mon Nov 07, 2011 11:02 am; edited 1 time in total

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    kaulnikhil GMAT Destroyer! Default Avatar
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    Post Sun May 08, 2011 10:28 pm
    GMATGuruNY wrote:
    netigen wrote:
    Running at their respective constant rates, machine X takes 2 days longer to produce w widgets than machine Y. At these rates, if the two machines together produce (5/4)w widgets in 3 days, how many days would it take machine X alone to produce 2w widgets?
    A. 4
    B. 6
    C. 8
    D. 10
    E. 12
    This question is from GMATPrep. An efficient way to solve this problem is to plug in the answer choices.

    Let w=12.
    In 3 days, X and Y need to produce 5/4*w = 5/4*12 = 15 widgets.
    The answer choices represent the time for X to produce 2w=24 widgets.

    Answer choice C: 8 days for X to produce 24 widgets
    Thus, X produces 12 widgets in 4 days.
    Since X takes 2 days longer, Y produces 12 widgets in 4-2=2 days.
    Rate for X = w/t = 12/4 = 3/day.
    Rate for Y = w/t = 12/2 = 6/day.
    Combined rate for X+Y = 3+6 = 9/day .
    Work completed in 3 days = r*t = 9*3 = 27 widgets.
    Incorrect. We need much less work to get done, so the time for X must be much longer.

    Answer choice E: 12 days for X to produce 24 widgets
    Thus, X produces 12 widgets in 6 days.
    Since X takes 2 days longer, Y produces 12 widgets in 6-2=4 days.
    Rate for X = w/t = 12/6 = 2/day.
    Rate for Y = w/t = 12/4 = 3/day.
    Combined rate for X+Y = 2+3 = 5/day.
    Work completed in 3 days = r*t = 5*3 = 15 widgets. Success!

    The correct answer is E.
    NICE

    jean.spellman Just gettin' started! Default Avatar
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    Post Mon May 13, 2013 5:33 pm
    Hello,

    Can anyone please explain how to get from:
    w/d + w/(d+2)

    To

    [2w(d+1)]/[d(d+2)]?

    Ty!

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