Help needed with the following:
(x-y)^2 = 0.
I understand that this translates to (x-y)(x-y) = 0. But kaplan says that this is the same as (x-y) = 0, why is this.
Thanks
Help with simple maths problem
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In simpler terms,
if (x-y)^2 = 0,
that means (x-y)(x-y)=0
Simple logic- if ZERO is the product of two numbers, one or both of those numbers HAS to be ZERO.
For eg. (1)(0)=0, (0)(534)=0 or (0)(0)=0
In this case, since you're squaring (x-y), and the answer is 0, that means x-y HAS TO BE 0.
Other than the number 0, no other number can mathematically square to 0.
Hope that was easier to understand than lines of equations.
if (x-y)^2 = 0,
that means (x-y)(x-y)=0
Simple logic- if ZERO is the product of two numbers, one or both of those numbers HAS to be ZERO.
For eg. (1)(0)=0, (0)(534)=0 or (0)(0)=0
In this case, since you're squaring (x-y), and the answer is 0, that means x-y HAS TO BE 0.
Other than the number 0, no other number can mathematically square to 0.
Hope that was easier to understand than lines of equations.
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