A hiker walking at a constant rate of 4 miles per hour is passed by a cyclist travelling in the same direction at t he rate of 20 miles per hour. The cyclist stops to wait for the hiker 5 minutes after passing her. While the hiker continues to walk at her constant rate, how many minutes must the cyclist wait until the hiker catches up?
1- 6 2/3
2- 15
3- 20
4- 25
5 - 26 2/3
I keep getting 2 even after converting the rates to minues. OA is C.
Gmatprep rates
This topic has expert replies
- jayhawk2001
- Community Manager
- Posts: 789
- Joined: Sun Jan 28, 2007 3:51 pm
- Location: Silicon valley, California
- Thanked: 30 times
- Followed by:1 members
The speed of the cyclist relative to the hiker = 20-4 = 16 mph
Since the cyclist travels for 5 min after passing the hiker, the
distance traveled by the cyclist = 16 * 5 / 60 miles
This distance can be traveled by the hiker in 16 * 5/60 * 1/4
= 20/60 hrs = 20 min
Since the cyclist travels for 5 min after passing the hiker, the
distance traveled by the cyclist = 16 * 5 / 60 miles
This distance can be traveled by the hiker in 16 * 5/60 * 1/4
= 20/60 hrs = 20 min
- jayhawk2001
- Community Manager
- Posts: 789
- Joined: Sun Jan 28, 2007 3:51 pm
- Location: Silicon valley, California
- Thanked: 30 times
- Followed by:1 members
All 'rate' values are in miles per "hour". So, you either have to convertmaolivie wrote:where did the 60 in the denominator to 5/60 come from?
rates to miles per minute OR convert time from minutes to hour for
proper calculation
We are given that the cyclist travels 5 minutes i.e. 5/60 hours.
-
- Newbie | Next Rank: 10 Posts
- Posts: 1
- Joined: Tue Dec 19, 2006 7:31 am
- Location: Boston, MA
Hello Guys,
I am new to the forum.
The biker passes the hiker and bikes for another 5 mins. So the distance traveled by biker is 5/3 miles in 5 mins.
The time that the biker is biking for 5 mins, the hiker is walking to so you have to take into acct the distance the hiker travels in 5 mins.
In 5 mins the hiker travels 1/3 miles. So the distance traveled by the hiker after the biker stops is 5/3 – 1/3 = 4/3.
The time the biker has to wait is therefore 4/3/4 = 4/12 = 1/3.
So the biker has to wait 1/3 hour which is equal to 1/3 X 60 = 20 mins.
I am new to the forum.
The biker passes the hiker and bikes for another 5 mins. So the distance traveled by biker is 5/3 miles in 5 mins.
The time that the biker is biking for 5 mins, the hiker is walking to so you have to take into acct the distance the hiker travels in 5 mins.
In 5 mins the hiker travels 1/3 miles. So the distance traveled by the hiker after the biker stops is 5/3 – 1/3 = 4/3.
The time the biker has to wait is therefore 4/3/4 = 4/12 = 1/3.
So the biker has to wait 1/3 hour which is equal to 1/3 X 60 = 20 mins.