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prasant Just gettin' started! Default Avatar
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GMATPrep Questions Post Sun May 13, 2007 2:14 pm
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  • Lap #[LAPCOUNT] ([LAPTIME])
    Hey Guys,

    I just finished taking a GMATPrep Practice Test and got the following quant questions wrong. Can someone please help me solve these problems? (I have fixed the mistake I made in #26)



    Thanks Smile

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    prasant Just gettin' started! Default Avatar
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    Post Sun May 13, 2007 2:16 pm
    Thanks to a lot that I learnt on this forum, I am finally getting to where I wanna be:



    I have my test scheduled for May 19.

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    Stacey Koprince GMAT Instructor
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    Post Thu May 17, 2007 8:25 pm
    Hi - you'll be more likely to get replies if you break your questions up into separate posts - most people who see so many questions in a row will be overwhelmed and move to another post. Smile

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    atarafder Just gettin' started! Default Avatar
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    Post Fri May 18, 2007 3:26 pm
    17.
    If Don had travelled the whole of x-miles at 60 mph, his travel time would have been t= x/60

    His actual travel time is = (x-5)/60 + 5/30
    = x/60 + 1/12

    This means that his travel time was increased by 1/12 hours.

    =(1/12)*100/x/60 = 500/x %

    atarafder Just gettin' started! Default Avatar
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    Post Fri May 18, 2007 3:32 pm
    26.
    1. Insufficient
    2. for the tip t be $8 the bill must be >=40 and </49
    15% of 49 <$7.5, so sufficient

    atarafder Just gettin' started! Default Avatar
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    Post Fri May 18, 2007 3:41 pm
    33.Let the # of cameras produced in 1993 = 100
    # of cameras in 1994 (x% more of that produced in 1993) = 100*(100+x)/100 = 100 + x

    # of cameras produced in 1995 (y% more than that produced in 1994) = (100+y) (100+x)/100 = 100 (1 + x+y + xy/100)

    1. Insufficent

    2. Sufficient

    bww Rising GMAT Star Default Avatar
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    Post Fri May 18, 2007 4:25 pm
    For #26...

    Isn't 1) sufficient? We know that Martin takes the tens digit of the amount of his bill x2 as the amount of his tip. Assuming his bill is $16, he would then leave a $2 tip. 15% of 16 if $1.80, so yes, the tip is greater than 15% of the amount of the bill. A 15% tip on a $49 bill would be $7.35, but Martin's rule of thumb has him leaving $8 as a tip. So, 1) is sufficient.

    2) If he leaves an $8 tip, then his bill must have been between $40-49. 15% tip on $40 is $6, and $7.35 on a $49 tab. 2) alone must also be sufficient...

    Answer is D?

    prasant Just gettin' started! Default Avatar
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    Post Fri May 18, 2007 9:50 pm
    Guys, Thanks for the responses. Very helpful.

    Sadowski Rising GMAT Star
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    Post Mon May 21, 2007 7:33 am
    bww wrote:
    For #26...

    Isn't 1) sufficient? We know that Martin takes the tens digit of the amount of his bill x2 as the amount of his tip. Assuming his bill is $16, he would then leave a $2 tip. 15% of 16 if $1.80, so yes, the tip is greater than 15% of the amount of the bill. A 15% tip on a $49 bill would be $7.35, but Martin's rule of thumb has him leaving $8 as a tip. So, 1) is sufficient.

    2) If he leaves an $8 tip, then his bill must have been between $40-49. 15% tip on $40 is $6, and $7.35 on a $49 tab. 2) alone must also be sufficient...

    Answer is D?
    Actually, 15% of $16 is $2.40, so his $2 tip is not greater than 15%. B is the only sufficient answer.

    mikeclarke44 Just gettin' started! Default Avatar
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    Post Sun Jun 10, 2007 2:33 pm
    #27
    I don't know why they posted it incorrect. I come up with a value for r when I use #1 and #2

    1). r=3m
    2). r/2 + m/2 =12 r + m = 24

    3m + m = 24
    4m = 24
    m= 6, r=18

    That answer should have been (C)

    mikeclarke44 Just gettin' started! Default Avatar
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    Post Sun Jun 10, 2007 2:34 pm
    #27
    I don't know why they posted it incorrect. I come up with a value for r when I use #1 and #2

    1). r=3m
    2). r/2 + m/2 =12 r + m = 24

    3m + m = 24
    4m = 24
    m= 6, r=18

    That answer should have been (C)

    vrider Just gettin' started! Default Avatar
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    Post Sun Jun 10, 2007 4:18 pm
    From (1) r=3m , insufficient
    From (2) r-12 = 12-m , insufficient

    combining, r-12 = 12 - r/3
    4/3*r = 24 or r = 18

    So, C?

    Hmm...I think I am missing something here...let me check.

    vrider Just gettin' started! Default Avatar
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    Post Sun Jun 10, 2007 4:27 pm
    Ok, I think I know why. Assumption that r=3m is wrong. If m is negative, distance from 0 to r can still be 3 times distance from m to 0 i.e. r=3m or r = -3m.

    Hence, combining (1) & (2) is still insufficient to find r.

    restero Just gettin' started! Default Avatar
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    Post Tue Mar 09, 2010 11:23 am
    #27 is E
    as r=3m or r=-3m

    solving u get 6, 18 and -12, 36; So E!

    harsh001 Just gettin' started! Default Avatar
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    Post Sat Mar 13, 2010 6:57 pm
    #19

    Let X = 1 and Y = 2 then equation = -1/3 < 1
    Let X = 1 and Y = -2 then equation = -3/2 < 1
    Let X =0 and Y = 1 then equation = 1 = 1
    Let X = 0 and Y =-1 then equation = -1 < 1
    Let X = -1 and Y = 2 then equation = -3 < 1
    Let X =-1 and Y = -2 then equation = -1/3 < 1

    therefore in all cases the equation in not greater than 1 if we take similar values of condition 2 we will see that each condition in its own answers the question therefore D is the answer!!

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