## GMATPrep Questions

This topic has
**2 expert replies** and **14 member replies**

**GMATPrep Questions**
* Sun May 13, 2007 1:14 pm*
Elapsed Time: **00:00**
- Lap #[LAPCOUNT] ([LAPTIME])

Hey Guys,

I just finished taking a GMATPrep Practice Test and got the following quant questions wrong. Can someone please help me solve these problems? (I have fixed the mistake I made in #26)

Thanks

* Sun May 13, 2007 1:16 pm*
Thanks to a lot that I learnt on this forum, I am finally getting to where I wanna be:

I have my test scheduled for May 19.

* Thu May 17, 2007 7:25 pm*
Hi - you'll be more likely to get replies if you break your questions up into separate posts - most people who see so many questions in a row will be overwhelmed and move to another post.

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* Fri May 18, 2007 2:26 pm*
17.

If Don had travelled the whole of x-miles at 60 mph, his travel time would have been t= x/60

His actual travel time is = (x-5)/60 + 5/30

= x/60 + 1/12

This means that his travel time was increased by 1/12 hours.

=(1/12)*100/x/60 = 500/x %

* Fri May 18, 2007 2:32 pm*
26.

1. Insufficient

2. for the tip t be $8 the bill must be >=40 and </49

15% of 49 <$7.5, so sufficient

* Fri May 18, 2007 2:41 pm*
33.Let the # of cameras produced in 1993 = 100

# of cameras in 1994 (x% more of that produced in 1993) = 100*(100+x)/100 = 100 + x

# of cameras produced in 1995 (y% more than that produced in 1994) = (100+y) (100+x)/100 = 100 (1 + x+y + xy/100)

1. Insufficent

2. Sufficient

* Fri May 18, 2007 3:25 pm*
For #26...

Isn't 1) sufficient? We know that Martin takes the tens digit of the amount of his bill x2 as the amount of his tip. Assuming his bill is $16, he would then leave a $2 tip. 15% of 16 if $1.80, so yes, the tip is greater than 15% of the amount of the bill. A 15% tip on a $49 bill would be $7.35, but Martin's rule of thumb has him leaving $8 as a tip. So, 1) is sufficient.

2) If he leaves an $8 tip, then his bill must have been between $40-49. 15% tip on $40 is $6, and $7.35 on a $49 tab. 2) alone must also be sufficient...

Answer is D?

* Fri May 18, 2007 8:50 pm*
Guys, Thanks for the responses. Very helpful.

* Mon May 21, 2007 6:33 am*
**bww wrote:**For #26...

Isn't 1) sufficient? We know that Martin takes the tens digit of the amount of his bill x2 as the amount of his tip. Assuming his bill is $16, he would then leave a $2 tip. 15% of 16 if $1.80, so yes, the tip is greater than 15% of the amount of the bill. A 15% tip on a $49 bill would be $7.35, but Martin's rule of thumb has him leaving $8 as a tip. So, 1) is sufficient.

2) If he leaves an $8 tip, then his bill must have been between $40-49. 15% tip on $40 is $6, and $7.35 on a $49 tab. 2) alone must also be sufficient...

Answer is D?

Actually, 15% of $16 is $2.40, so his $2 tip is not greater than 15%. B is the only sufficient answer.

* Sun Jun 10, 2007 1:33 pm*
#27

I don't know why they posted it incorrect. I come up with a value for r when I use #1 and #2

1). r=3m

2). r/2 + m/2 =12 r + m = 24

3m + m = 24

4m = 24

m= 6, r=18

That answer should have been (C)

* Sun Jun 10, 2007 1:34 pm*
#27

I don't know why they posted it incorrect. I come up with a value for r when I use #1 and #2

1). r=3m

2). r/2 + m/2 =12 r + m = 24

3m + m = 24

4m = 24

m= 6, r=18

That answer should have been (C)

* Sun Jun 10, 2007 3:18 pm*
From (1) r=3m , insufficient

From (2) r-12 = 12-m , insufficient

combining, r-12 = 12 - r/3

4/3*r = 24 or r = 18

So, C?

Hmm...I think I am missing something here...let me check.

* Sun Jun 10, 2007 3:27 pm*
Ok, I think I know why. Assumption that r=3m is wrong. If m is negative, distance from 0 to r can still be 3 times distance from m to 0 i.e. r=3m or r = -3m.

Hence, combining (1) & (2) is still insufficient to find r.

* Tue Mar 09, 2010 10:23 am*
#27 is E

as r=3m or r=-3m

solving u get 6, 18 and -12, 36; So E!

* Sat Mar 13, 2010 5:57 pm*
#19

Let X = 1 and Y = 2 then equation = -1/3 < 1

Let X = 1 and Y = -2 then equation = -3/2 < 1

Let X =0 and Y = 1 then equation = 1 = 1

Let X = 0 and Y =-1 then equation = -1 < 1

Let X = -1 and Y = 2 then equation = -3 < 1

Let X =-1 and Y = -2 then equation = -1/3 < 1

therefore in all cases the equation in not greater than 1 if we take similar values of condition 2 we will see that each condition in its own answers the question therefore D is the answer!!