GMATPrep Modulus Question

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GMATPrep Modulus Question

by Mo2men » Tue Oct 18, 2016 12:47 am
If y≥0, what is the value of x?

(1) |x−3|≥y

(2) |x−3|≤−y

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by GMATGuruNY » Tue Oct 18, 2016 4:17 am
Mo2men wrote:If y≥0, what is the value of x?

(1) |x−3|≥y

(2) |x−3|≤−y
Statement 1: |x−3| ≥ y
If y=0, then |x-3| ≥ 0.
|x-3| ≥ 0 for any value of x.
Since x can be any value, INSUFFICIENT.

Statement 2: |x-3| ≤ -y
Since an absolute value cannot be less than or equal to a negative value, the right side of this inequality must be NONNEGATIVE:
-y≥0
y≤0.
According to the prompt, 0≤y.
Linking together the inequalities in blue, we get:
0≤y≤0.
The only value that satisfies the resulting inequality is y=0.

Substituting y=0 into |x-3| ≤ -y, we get:
|x-3| ≤ -0
|x-3| ≤ 0.

Since an absolute value cannot be negative, it is not possible that |x-3| < 0.
|x-3| = 0 if x=3.
Thus, the only possible value for x is 3.
SUFFICIENT.

The correct answer is B.
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by fiza gupta » Sat Oct 22, 2016 11:18 am
given y>=0

1) |x-3| >= y
x can take any value, because mod will make |x-3| positive
example x = -3
|-6| = 6
INSUFFICIENT

2) |x-3|>= -y
mod will always be positive or 0
mod can never be negative
hence x will be 3 to make y=0 because cannot be negative
x = 3 and y =0
SUFFICIENT

SO B
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by [email protected] » Sat Oct 22, 2016 5:52 pm
Hi Mo2men,

This question can be solved by TESTing VALUES.

We're told that Y ≥ 0. We're asked for the value of X.

1) |X - 3| ≥ Y

IF....
Y = 0, X could be ANY value.
Fact 1 is INSUFFICIENT

2) |X - 3| ≤ -Y

With this Fact, you should notice that we're dealing with NEGATIVE Y. The prompt tells us that Y is 0 or positive though. Since absolute values cannot have negative results, when combining these two pieces of information, the ONLY possible value of Y IS 0.

|X - 3| ≤ 0

Under these circumstances, X can only be 3.
Fact 2 is SUFFICIENT

Final Answer: B

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