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gmat prep

This topic has 3 member replies
yvonne12 Master | Next Rank: 500 Posts Default Avatar
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gmat prep

Post Wed Mar 07, 2007 3:27 pm
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    2 members of a club are to be selected to represent the club at a national meeting. if there are 190 different possible selections of 2 members, how many members does the club have?

    please explain

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    Argen Junior | Next Rank: 30 Posts Default Avatar
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    Post Wed Mar 07, 2007 4:15 pm
    nC2=n!/((n-2)!2!)=190
    n(n-1)=380
    n=20

    yvonne12 Master | Next Rank: 500 Posts Default Avatar
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    Post Wed Mar 07, 2007 9:23 pm
    thank you

    Cybermusings Legendary Member Default Avatar
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    Post Tue Mar 27, 2007 1:58 am
    190 selections of "n" members taken 2 at a time...

    Which means nC2 = 190

    n! /(n-2)! * 2! = 190

    n*n-1*n-2!/n-2!*2=190

    n*n-1=380
    Therefore n=20

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