GMAT Prep

New MBA Student Life Forum: Ask your questions to current MBA students from Harvard, Stanford, Wharton, Kellogg and Haas

Post new topic   Reply to topic

atlantic
Really wants to Beat The GMAT!



Joined: 27 Apr 2008
Posts: 132

Thanks given: 2
Thanked 7 times in 7 posts
Location: Portugal

Target GMAT Score: 650

Topic: GMAT Prep
PostSun Jun 29, 2008 10:18 am Reply with quote

Hi guys,

Your help is kindly requested for this one,

post OA latter
Attachments
This post contains an attachment. You must be logged in to download/view this file. Please login or register as a user.
Back to top
View user's profile Send private message
Ian Stewart
GMAT Instructor



Joined: 02 Jun 2008
Posts: 1472

Thanks given: 4
Thanked 385 times in 315 posts
Location: London

GMAT Score: 780

PostSun Jun 29, 2008 1:03 pm Reply with quote

First, the question asks: is |x - z| + |x| = |z|. I find this easiest to think about if I understand what the equation says about distances. Remember that |a - b| is just the distance between a and b on the number line, and |a| is the distance from a to zero. So |x - z| + |x| = |z| just says "the distance between x and z plus the distance from x to zero is equal to the distance from z to zero". How can this happen? Draw a number line, try placing x and z in different orders and on either side of zero, and you can see that this can only happen in two ways:

z < x < 0
0 < x < z

So the question is just asking- can we be sure that one of the above inequalities is true?

Before looking at the statements, we know that zy < xy < 0. What does this tell us?

-Either y is negative, and both x and z are positive, or y is positive, and both x and z are negative.

-Because zy - xy < 0, y(z-x) <0. If y is negative, then z-x must be positive, and z > x. If y is positive, z-x must be negative, and z < x (and, conversely, if z < x, y must be positive).

Okay, that was the tough part. Let's look at the statements:
1) z < x

If z < x, we know that y must be positive. If y is positive, x and z are both negative. So we know that z < x <0, and the answer to the question must be yes.

2) y > 0

If y is positive, well, this is exactly the same situation as we had with Statement 1. So again, z < x < 0, and the answer to the question must be yes.

D.

_________________
co-founder, www.gmatix.com
-GMAT blogs, free international directory of GMAT tutors and MBA Admissions Consultants, and more...
Back to top
View user's profile Send private message
Thanked by: nandistl, havocsummers
atlantic
Really wants to Beat The GMAT!



Joined: 27 Apr 2008
Posts: 132

Thanks given: 2
Thanked 7 times in 7 posts
Location: Portugal

Target GMAT Score: 650

PostMon Jun 30, 2008 3:46 am Reply with quote

Thanks Ian. Your explanation was of great help.
Back to top
View user's profile Send private message
Display posts from previous:   

Post new topic   Reply to topic All times are GMT - 8 Hours
Page 1 of 1