Of the 60 animals on a certain farm, 2/3 are either pigs or cows. How many of the animals are cows?

I. The farm has more than twice as many cows as it has pigs

II. the firm has mroe than 12 pigs

I thought it was I since 60(2/3)=40 and p=2c and p+c=40 sp, 2c +c =40, c=13 and you can get your answer that way, but the answer is c. why??

Of the 60 animals on a certain farm, 2/3 are either pigs or cows. How many of the animals are cows?

I. The farm has more than twice as many cows as it has pigs

II. the firm has mroe than 12 pigs

Statement I- 2/3 either pigs or cows. Thus the remainder i.e. 1/3 are neither cows nor pigs (1/3*60) = 20
So cows + pigs = 60-20 = 40
Now if pigs are x, cows = >2x
This statement alone is insufficient

Statement II
Firm has more than 12 pigs. All we know is that cow and pigs are 40 and out of these pigs are more than 12. This is insufficient

Both together
x + y = 40
x>12
y>2x (where y is the number of cows)
If pigs are 13, cows would be 27, which is more than twice the number of pigs
If pigs are 14, cows would be 26, which is less than twice the number of pigs. This violates the statements

Hence Answer is C. Two statements together are correct but neither one alone