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gmat prep question

This topic has 4 member replies
yvonne12 Master | Next Rank: 500 Posts Default Avatar
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gmat prep question

Post Tue Apr 10, 2007 3:29 pm
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    If the operation [@] is one of the four arithmetic operations addition, subtraction, multiplication and division is (6@2)@4=6@(2@4)

    I. 3@2>3

    II. 3@1=3

    the answer is I alone, but how can this be if either 3x2 =6 or 3+2 = 5[/code]

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    jayhawk2001 Community Manager
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    Post Tue Apr 10, 2007 10:11 pm
    1 - sufficient. 3 @ 2 > 3 implies @ is either + or *.
    For both + and *, (6@2)@4=6@(2@4)

    2 - insufficient. @ can be either * or /.
    If we use /, (6/2)/4 != 6/(2/4)
    If we use *, (6*2)*4 = 6*(2*4)

    Hence A

    yvonne12 Master | Next Rank: 500 Posts Default Avatar
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    Post Wed Apr 11, 2007 8:22 am
    So the first has two arithmetic signs + and x, but if they both give the same answer on both sides of the equation then the answer is sufficient? so for future, how do I approach these kinds of questions?

    Even if there are 2 possible signs, as long as they give me the same number on both sides of the equation then its suffient, right?

    Cybermusings Legendary Member Default Avatar
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    Post Thu Apr 12, 2007 8:12 am
    If the operation [@] is one of the four arithmetic operations addition, subtraction, multiplication and division is (6@2)@4=6@(2@4)

    I. 3@2>3

    II. 3@1=3

    3@2>3. Thus @ for sure can't be division or subtraction. But it can be either addition or multiplication in in both cases the result would be greater than 3.
    Now if @ is addition then (6@2)@4 would be (6+2)+4 = 6+2+4=12; and 6@(2@4)=6+(2+4)=6+2+4=12
    If @ is multiplication then (6@2)@4=(6*2)*4=48; and 6@(2@4)=6*(2*4)=48
    Hence in both cases (6@2)@4=6@(2@4)
    Hence alone sufficient

    3@1=3. Here @ can be multiplication or division. If @ we know that the two sides of the equation would be the same. But in case of division
    (6/2)/4 is not equal to 6/(2/4)
    First value = 3/4
    Second value = 12

    Hence Answer is A

    yvonne12 Master | Next Rank: 500 Posts Default Avatar
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    Post Thu Apr 12, 2007 9:11 am
    I get it now, thanks

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