Function 2

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Function 2

by NaimaB » Sat Dec 06, 2014 9:09 am
Given f(x) = 3x-5, for what value of x does 2*[f(x)-1] = f(3x-6)?

(A) 0

(B) 4

(C) 6

(D) 7

(E) 13

What is the shortcut way to solve this kind of problem?

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by GMATGuruNY » Sun Dec 07, 2014 5:00 am
The problem has been transcribed incorrectly.
It should read as follows:
Given f(x) = 3x-5, for what value of x does 2f(x) - 1 = f(3x-6)?

(A) 0

(B) 4

(C) 6

(D) 7

(E) 13
We can PLUG IN THE ANSWERS, which represent the value of x.
When the correct answer choice is plugged in, 2f(x) - 1 = f(3x-6).

Both the original function -- f(x) = 3x-5 -- and the equation above involve multiplication.
Generally, the smaller the value, the less the value will be affected by multiplication.
Implication:
2f(x) - 1 = f(3x-6) will likely be true for a relatively small value of x.

Answer choice B: x=4
2f(x) - 1:
f(x) = f(4) = 3*4 - 5 = 7.
Thus, 2f(x) - 1 = 2*7 - 1 = 13.

f(3x - 6):
f(3x - 6) = f(3*4 - 6) = f(6).
f(6) = 3*6 - 5 = 13.

Success!
2f(x) - 1 = f(3x-6) = 13.

The correct answer is B.
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by [email protected] » Sun Dec 07, 2014 12:48 pm
Hi NaimaB,

I'm a big fan of TESTing THE ANSWERS (the approach that Mitch used); this question can also be solved algebraically.

We're given the function: f(X) = 3X - 5

We're given an equation that uses the function, so we can plug in the respective values (X and [3X-6]) into the function and solve:

2f(X) - 1 = f(3X - 6)

Left side:
2[f(X)] - 1 = 2(3X - 5) - 1 = 6X - 10 - 1 = 6X - 11

Right side:
f(3X - 6) = 3(3X-6) - 5 = 9X - 18 - 5 = 9X - 23

Now set them equal to one another:

6X - 11 = 9X - 23
12 = 3X
4 = X

Final Answer: B

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