FRACTIONS: MGMAT

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FRACTIONS: MGMAT

by Calexis23 » Thu Sep 10, 2015 1:04 pm
Bradley owns b video game cartridges. If Bradley's total is one-third the total owned by Andrew and four times the total owned by Charlie, how many video games cartridges do the three own altogether, in terms of b?

A) 16/3b
B)17/4b
C)13/4b
D)19/12b
E)7/12b

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by Brent@GMATPrepNow » Thu Sep 10, 2015 1:09 pm
Calexis23 wrote:Bradley owns b video game cartridges. If Bradley's total is one-third the total owned by Andrew and four times the total owned by Charlie, how many video games cartridges do the three own altogether, in terms of b?

A) (16/3)b
B) (17/4)b
C) (13/4)b
D) (19/12)b
E) (7/12)b
# of cartridges owned by Bradley = b
# of cartridges owned by Andrew = 3b
# of cartridges owned by Charlie = b/4

TOTAL # of cartridges = b + 3b + b/4
Rewrite with a common denominator of 4 to get: 4b/4 + 12b/4 + b/4
Combine to get: [spoiler]17b/4[/spoiler]

Answer: B

Cheers,
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Last edited by Brent@GMATPrepNow on Thu Sep 10, 2015 1:57 pm, edited 1 time in total.
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by DavidG@VeritasPrep » Thu Sep 10, 2015 1:17 pm
Bradley owns b video game cartridges. If Bradley's total is one-third the total owned by Andrew and four times the total owned by Charlie, how many video games cartridges do the three own altogether, in terms of b?

A) 16/3b
B)17/4b
C)13/4b
D)19/12b
E)7/12b
Say Bradley owns 4 video games, so b = 4.
If Bradley's total of 4 is 1/3 the total owned by Andrew, Andrew owns 12 video games.
If Bradley owns 4 times the amount Charlie owns, then Charlie owns 1 video game.

Together, they own 4 + 12 + 1 = 17. So when b = 4, we get a total of 17.

When we plug 4 in for b, no answer choice gives us 17 the way they're currently written, so I'm assuming, they should read:

A) (16/3)b
B)( 17/4)b
C) (13/4)b
D) (19/12)b
E) (7/12)b

When we plug b = 4 into B we get 17, so this is our answer.
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by Brent@GMATPrepNow » Thu Sep 10, 2015 1:56 pm
David and I have demonstrated the two approaches to questions with variables in the answer choices:
- Algebraic approach
- Input-Output approach

If you're interested, we have free videos on both approaches:
https://www.gmatprepnow.com/module/gmat- ... /video/933
https://www.gmatprepnow.com/module/gmat- ... /video/934
https://www.gmatprepnow.com/module/gmat- ... /video/935

Cheers
Brent
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