f(x) = f(1-x) function problem q

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czechchamp
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Topic: f(x) = f(1-x) function problem q
PostSun Jul 06, 2008 3:13 pm
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f(x) = f(1-x)

A f(x) = 1-x
B f(x) = 1-x^2
C f(x) = x^2 - (1-x)^2
D d. f(x) = x^2(1-x)^2 EDITED
E f(x) = x / 1-x

The correct answer is D. However, can someone elaborate on how to approach the problem? If I substitute 2 in D I get f(2) = 4 (1-2)^2 =>
2 = 4. What am I missing?

Last edited by czechchamp on Mon Jul 07, 2008 7:40 am; edited 1 time in total
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sibbineni
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PostSun Jul 06, 2008 8:10 pm
f(x) = f(1-x)

let us consider the choices:

option D
f(x)=x^2*(1-x)^2----(1)

substitute 1-x in the place of x in equation 1we have
f(1-x)=(1-x)^2*(1-(1-x))^2
==>(1-x)^2*(x)^2==>x^2*(1-x)^2----(2)

1=2

so Option D only satisfies


(OR)


The correct answer is D. However, can someone elaborate on how to approach the problem? If I substitute 2 in D I get f(2) = 4 (1-2)^2 =>
2 = 4. What am I missing?


f(x)=x^2*(1-x)^2 ----(a)

substitute 2 in equation (a)
==>4(1-2)^2==>4

f(1-x)==>f(1-2)==>f(-1)

so substitute f(-1 ) in equation (a)

==(-1)^2(1-(-1))^2==>2^2==>4


so D is the answer
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moontashir
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PostSun Jul 06, 2008 11:03 pm
is it a typo...option D doesnt seem to be right
it says (1-x)

Whereas in the solution it sez (1-x)^2

Please correct me if im wrong
im just a newbie...
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sibbineni
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PostMon Jul 07, 2008 5:57 am
czechchamp wrote

If I substitute 2 in D I get f(2) = 4 (1-2)^2 =>
2 = 4. What am I missing?

so,option D should be

f(x) = x^2 (1-x)^2

i think he forgot to write ^2 in option D
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czechchamp
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PostMon Jul 07, 2008 7:39 am
sibbineni wrote:
czechchamp wrote

If I substitute 2 in D I get f(2) = 4 (1-2)^2 =>
2 = 4. What am I missing?

so,option D should be

f(x) = x^2 (1-x)^2

i think he forgot to write ^2 in option D
Yes, indeed, I keyed it in wrong. The option D as noted above should be f(x) = x^2(1-x)^2

Thanks for your explanation! Smile
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jsl
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PostMon Jul 07, 2008 8:21 am
on this type of question - is the best/quickest way to solve this equation to plug in the functions into each of the answer choices? Is there a special GMAT shortcut or is this question painfully slow?
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aj5105
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PostWed Oct 08, 2008 3:56 am
As I have learnt,depends form problem to problem.

Here just substitute (1-x) for all functions.
We get f(x)=f(1-x)=f(x) right away.
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510_At_It_Again
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PostSat May 16, 2009 4:41 am
is there a more simple way to word this question? What is being asked is very convoluted.
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silentdud
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PostFri May 29, 2009 1:32 pm
[quote="aj5105"]As I have learnt,depends form problem to problem.

Here just substitute (1-x) for all functions.
We get f(x)=f(1-x)=f(x) right away.


EDIT: actually that seems to be the fastest way
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vineetbatra
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PostSat Jun 27, 2009 2:29 pm
I am having a lot of trouble understanding these type of a problems. Can someone please explain this in the most rudimentary way, from the basics of what is f(x) to what the question is seeking.

It will be greatly appreciated.

Thanks,

Vineet
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Matmasi
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PostFri Aug 28, 2009 11:41 am
Hi, I had hard times also.
The question gives you 5 different functions and asks for which of the functions plugging in the value of x gives the same result of plugging (1-x).

basically, just substitute (1-x)at x and see if they give you the same result:
for example if you look at the first function:
F(x)=1-x
F(1-x) = 1-(1-x)=-x
They give you different results so this functions is not that function that gives you the same result using x or (1-x).

Let's have a look to the right one (D).
F(X)= (x^2) * (1-x)^2
F(1-X)= (1-x)^2 * ((1-(1-x))^2 = (1-x)^2 * (-x)^2 = (1-x)^2 * x^2
So you get that same equation using x or (1-x).

Goof luck for your studies.
Mat
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CarpeDiem2011
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PostMon Nov 16, 2009 2:25 pm
I'm not sure I understand this.

So we plug in x-1 for x for all the equations. Then what are we looking out for that gives D as the answer?

Thanks!
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