Triangle ABC has AC = BC, and ∠ACB = 96°. D is a point in triangle ABC such that ∠DAB = 18° and ∠DAB = 30°. What is the measure (in degrees) of ∠ACD?
https://www5.esc13.net/thescoop/math/201 ... can-solve/
Dylan solved this ridiculously hard geometry problem
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That kid certainly does look exceptionally bright. This particular problem is very challenging, certainly beyond the GMAT. Below is an attached diagram.sanju09 wrote:Triangle ABC has AC = BC, and ∠ACB = 96°. D is a point in triangle ABC such that ∠DAB = 18° and ∠DAB = 30°. What is the measure (in degrees) of ∠ACD?
https://www5.esc13.net/thescoop/math/201 ... can-solve/
We know, by the 1800-Triangle Theorem, angle ADB = 132 degrees.
From addition addition, we also know:
angle CAD = 24 degrees
angle CBD = 12 degrees
It appears we have four unknowns, the angles labeled a, b, c, and d. We know
1) at vertex C
a + d = 96
2) In Triangle ACD
24 + a + b = 180
a + b = 156
3) In Triangle BCD
12 + c + d = 180
c + d = 168
4) at vertex D
132 + b + c = 360
b + c = 228
That's four unknowns and four equations, but the trouble is, those four equations are not independent: we get two different ways to get
a + b + c + d = 324
I believe we would need to use trigonometry. We could pick an arbitrary length for AB, and use the Law of Sines to find AC = BC, AD, and BD. From angle CAD, we could use the law of cosines to find length CD, and then use the Law of Sines or Cosines to solve for the angle. That would work, but it's a rather unsatisfying approach, because we would have to use an inverse trig function to give us the angle. There should be a way to do it with pure geometry, without having to use inverse trig functions.
From the software I used to create the diagram, I did find that the angle is 78 degrees. Of course, that's cheating. The computer found the answer, not I.
I would be intrigued to see any purely geometric solution to this problem. Great problem, sanju09!
Mike
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I cannot think of a purely geometric solution, but here's a trig one that isn't too cumbersome:
After we find angles ADB, CAD, and CBD as mentioned by Mike@Magoosh, use the Law of Sines on the main triangle:
AB/(sin 96) = AC/(sin 42)
AB/AC = Sin 96 / sin 42
Convert demoninator to cos --> AB/AC = sin 96 / cos 48
Use the Sin(2A) conversion on numerator --> AB/AC = 2 sin 48 cos 48 / cos 48
Cancel out and simplify --> AB = AC * (2 sin 48)
Now use the Law of Sines on triangle ADB
AB / sin 132 = AD / sin 30
AB/AD = sin 132 / sin 30
Sin 132 = sin 48, and sin 30 = 1/2, so now we have --> AB/AD = 2 sin 48
So AB = AD * (2 sin 48)
Based on this, AC = AD. And since we know that Angle DAC is 24, Angle ACD = Angle ADC = 78
After we find angles ADB, CAD, and CBD as mentioned by Mike@Magoosh, use the Law of Sines on the main triangle:
AB/(sin 96) = AC/(sin 42)
AB/AC = Sin 96 / sin 42
Convert demoninator to cos --> AB/AC = sin 96 / cos 48
Use the Sin(2A) conversion on numerator --> AB/AC = 2 sin 48 cos 48 / cos 48
Cancel out and simplify --> AB = AC * (2 sin 48)
Now use the Law of Sines on triangle ADB
AB / sin 132 = AD / sin 30
AB/AD = sin 132 / sin 30
Sin 132 = sin 48, and sin 30 = 1/2, so now we have --> AB/AD = 2 sin 48
So AB = AD * (2 sin 48)
Based on this, AC = AD. And since we know that Angle DAC is 24, Angle ACD = Angle ADC = 78
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Dear dimochka,
I commend you for an elegant trig solution. But since the angle we seek has an integer value, there absolutely must be a clean geometric way to find it directly, without changing it into trig decimals and then changing it back. That's what is truly challenging about this problem.
Mike
I commend you for an elegant trig solution. But since the angle we seek has an integer value, there absolutely must be a clean geometric way to find it directly, without changing it into trig decimals and then changing it back. That's what is truly challenging about this problem.
Mike
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While, honestly i found this problem pretty easy, you have referred to DAB twice in the question as 18 degrees. Hope I havent got it wrong !
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Hi All,
Not to put too fine a point on this thread and the news article that serves as the source, but what does this have to do with the GMAT? I'll grant the somewhat interesting aspect of the material (because I'm a nerd), but posting it here only serves to distract Test Takers with beyond-the-boundaries-of-the-GMAT material.
GMAT assassins aren't born, they're made,
Rich
Not to put too fine a point on this thread and the news article that serves as the source, but what does this have to do with the GMAT? I'll grant the somewhat interesting aspect of the material (because I'm a nerd), but posting it here only serves to distract Test Takers with beyond-the-boundaries-of-the-GMAT material.
GMAT assassins aren't born, they're made,
Rich
After we find angles ADB, CAD, and CBD as mentioned by Mike@Magoosh, use the Law of Sines on the main triangle:
AB/(sin 96) = AC/(sin 42)
AB/AC = Sin 96 / sin 42
Convert demoninator to cos --> AB/AC = sin 96 / cos 48
Use the Sin(2A) conversion on numerator --> AB/AC = 2 sin 48 cos 48 / cos 48
Cancel out and simplify --> AB = AC * (2 sin 48) ????
AB/(sin 96) = AC/(sin 42)
AB/AC = Sin 96 / sin 42
Convert demoninator to cos --> AB/AC = sin 96 / cos 48
Use the Sin(2A) conversion on numerator --> AB/AC = 2 sin 48 cos 48 / cos 48
Cancel out and simplify --> AB = AC * (2 sin 48) ????
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