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## DS OG 12 # 152

This topic has 1 expert reply and 3 member replies
HPengineer Master | Next Rank: 500 Posts
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#### DS OG 12 # 152

Thu Aug 12, 2010 8:39 pm
If Carmen had 12 more tapes she would have twice as many tapes as Rafael. Does Carmen have fewer tapes then Rafael?

S1. Rafael has more then 5 tapes
S2. Carmen has fewer than 12 tapes

I got this right however i think it was by accident. Any one care to share their approach with me and so we can compare?

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nasir Senior | Next Rank: 100 Posts
Joined
13 Oct 2009
Posted:
55 messages
3
Sat Sep 04, 2010 11:10 pm
@HPengineer:

i solved it in the same way......

HPengineer Master | Next Rank: 500 Posts
Joined
24 Mar 2010
Posted:
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Sat Aug 14, 2010 3:50 am
Ok heres how i solved it... Im wondering if its dangerous to solve similar probems with out inequalities...

S1. Rafael has more then 5 tapes

C + 12 = 2R so plug 6 in for R and solve for C which = 0 so less tapes then Rafael

Now try a larger number say 20 for R and you will get C = 38 which is more tapes then Rafaeal therefore S1 is Insuff.

S2. Carmen has fewer than 12 tapes

Here i simply plugged in 11 for C and solved for R

11+12= 2R or 23/2 = R so R = 11.5 which is greater then C so statement is sufficient.

What troubled me here is that i did not get a integer for R... How can you have half a tape? Shouldnt this be a hidden constraint problem since were dealing with items?

nasir Senior | Next Rank: 100 Posts
Joined
13 Oct 2009
Posted:
55 messages
3
Sat Sep 04, 2010 11:10 pm
@HPengineer:

i solved it in the same way......

HPengineer Master | Next Rank: 500 Posts
Joined
24 Mar 2010
Posted:
165 messages
Followed by:
1 members
2
Sat Aug 14, 2010 3:50 am
Ok heres how i solved it... Im wondering if its dangerous to solve similar probems with out inequalities...

S1. Rafael has more then 5 tapes

C + 12 = 2R so plug 6 in for R and solve for C which = 0 so less tapes then Rafael

Now try a larger number say 20 for R and you will get C = 38 which is more tapes then Rafaeal therefore S1 is Insuff.

S2. Carmen has fewer than 12 tapes

Here i simply plugged in 11 for C and solved for R

11+12= 2R or 23/2 = R so R = 11.5 which is greater then C so statement is sufficient.

What troubled me here is that i did not get a integer for R... How can you have half a tape? Shouldnt this be a hidden constraint problem since were dealing with items?

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