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DS OG 12 # 152

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HPengineer Master | Next Rank: 500 Posts Default Avatar
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DS OG 12 # 152

Post Thu Aug 12, 2010 8:39 pm
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    If Carmen had 12 more tapes she would have twice as many tapes as Rafael. Does Carmen have fewer tapes then Rafael?

    S1. Rafael has more then 5 tapes
    S2. Carmen has fewer than 12 tapes



    I got this right however i think it was by accident. Any one care to share their approach with me and so we can compare?

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    sanju09 GMAT Instructor
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    Post Thu Aug 12, 2010 9:04 pm
    HPengineer wrote:
    If Carmen had 12 more tapes she would have twice as many tapes as Rafael. Does Carmen have fewer tapes then Rafael?

    S1. Rafael has more then 5 tapes
    S2. Carmen has fewer than 12 tapes



    I got this right however i think it was by accident. Any one care to share their approach with me and so we can compare?
    Take C + 12 = 2 R from stem. C will always be EVEN as C and R are whole numbers. Then try answering if C < R.

    S1. If R > 5, then C + 12 is at least 12 as C and R are whole numbers. When R is 6, C is 0, making C < R as true, but when R is 12, C = R. So insufficient

    S2. If C < 12, then it can at most be 10 to ensure C and R are whole numbers. When C is 10, R is 11, making C < R as true, which remains as true for all smaller possibilities for C. So sufficient

    B

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    clock60 Legendary Member Default Avatar
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    Post Fri Aug 13, 2010 12:15 pm
    also got B
    the number of tapes Carmen-c
    the number of tapes Rafael-r
    we are given
    c+12=2r
    r=c/2+6
    and asked if r>c, or
    (c/2+6)-c>0
    c+12-2c>0
    is c<12
    (1) insuffiicent, here to answer definitely we need to prove that r<12, but given that r>5
    (2) c<12 suffiicent

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    HPengineer Master | Next Rank: 500 Posts Default Avatar
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    Post Sat Aug 14, 2010 3:50 am
    Ok heres how i solved it... Im wondering if its dangerous to solve similar probems with out inequalities...

    S1. Rafael has more then 5 tapes

    C + 12 = 2R so plug 6 in for R and solve for C which = 0 so less tapes then Rafael

    Now try a larger number say 20 for R and you will get C = 38 which is more tapes then Rafaeal therefore S1 is Insuff.



    S2. Carmen has fewer than 12 tapes

    Here i simply plugged in 11 for C and solved for R

    11+12= 2R or 23/2 = R so R = 11.5 which is greater then C so statement is sufficient.

    What troubled me here is that i did not get a integer for R... How can you have half a tape? Shouldnt this be a hidden constraint problem since were dealing with items?

    nasir Senior | Next Rank: 100 Posts
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    Post Sat Sep 04, 2010 11:10 pm
    @HPengineer:

    i solved it in the same way...... Very Happy

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