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ds#20

This topic has 2 member replies
dunkin77 Master | Next Rank: 500 Posts Default Avatar
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Posted:
269 messages

ds#20

Post Thu May 03, 2007 2:54 am
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    If Carmen had 12 more tapes, she would have twice as many tapes as Rafael. Does Carmen have fewer tapes than Rafael?
    (1) Rafael has more than 5 tapes.
    (2) Carmen has fewer than 12 tapes.




    Hi,
    I thought the answer was E) but the text says B) -- Can anyone confirm?

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    mschling52 Master | Next Rank: 500 Posts Default Avatar
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    Post Thu May 03, 2007 7:47 am
    I think B is right. The stem gives us the equation

    R = (C+12)/2

    and the question is C<R? If C<R, then

    C < (C+12)/2
    2C < C+12
    C<12

    So, if we know that C < 12, then we also know that C < R.

    (1) alone only gives us R > 5. If R = 6, then C = 0 and C<R. However, if R=15, then C=18 and C>R, so (1) Alone is not sufficient.

    (2) alone, however, gives us C<12, which is sufficient by the logic above.

    moneyman Master | Next Rank: 500 Posts Default Avatar
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    Post Wed May 09, 2007 7:11 am
    If Carmen had 12 more tapes, she would have twice as many tapes as Rafael. Does Carmen have fewer tapes than Rafael?
    (1) Rafael has more than 5 tapes.
    (2) Carmen has fewer than 12 tapes.

    From the question the equation c+12=2r can be obtained now we just have to look out for the value of c or r to solve the problem.

    (1)is not sufficient because if r>5 can be any number and hence will result in many values.

    (2) is sufficent because if c<12 and c+12=2r then c will have a range of values from 1-11.By substituting the value of c as 11 c becomes 23 and so the value of r can be obtained as 11.5.Since the maximum value of c can only be 11 and by substituting the values in the equation we get the value of r as 11.5 the question is answered as r>c.

    I hope my way of doing this problemn helped you..

    _________________
    Maxx

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