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Difficult Math Question #12

This topic has 2 member replies
800guy Master | Next Rank: 500 Posts Default Avatar
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Difficult Math Question #12

Post Mon Sep 11, 2006 7:44 pm
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    OA after a few people answer..

    The average of temperatures at noontime from Monday to Friday is 50; the lowest one is 45, what is the possible maximum range of the temperatures?

    A) 20

    B) 25

    C) 40

    D) 45

    E) 75

    Thanked by: karthik1239
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    jayofbay Junior | Next Rank: 30 Posts Default Avatar
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    Posted:
    25 messages
    Post Tue Sep 12, 2006 12:05 am
    5x50 = 45x4 + x
    x = 70
    Hence range is 70-45=25

    Answer is B

    800guy Master | Next Rank: 500 Posts Default Avatar
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    Post Wed Sep 13, 2006 7:12 pm
    OA:

    The answer 25 doesn't refer to a temperature, but rather to a range of temperatures.

    The average of the 5 temps is: (a + b + c + d + e) / 5 = 50
    One of these temps is 45: (a + b + c + d + 45) / 5 = 50
    Solving for the variables: a + b + c + d = 205
    In order to find the greatest range of temps, we minimize all temps but one. Remember, though, that 45 is the lowest temp possible, so: 45 + 45 + 45 + d = 205
    Solving for the variable: d = 70
    70 - 45 = 25

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