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Difficult Math Problem #79 - Number Theory

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800guy Master | Next Rank: 500 Posts Default Avatar
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Difficult Math Problem #79 - Number Theory

Post Fri Dec 22, 2006 10:39 am
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    How many positive integers less than 5,000 are evenly divisible by neither 15 nor 21?

    A. 4,514
    B. 4,475
    C. 4,521
    D. 4,428
    E. 4,349

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    aim-wsc Legendary Member
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    Post Sat Dec 23, 2006 5:10 am
    5000/15 = 333 quotient & 5 remainder

    5000/21 = 238 quotient & 2 remainder

    LCM for 15 & 21 =105

    5000/105 = 47 quotient

    5000-333-238+47 = 4476

    ANSWER :
    4475

    C'mon 800guy i dont think they will ask such questions...

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    thankont Senior | Next Rank: 100 Posts
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    Post Mon Dec 25, 2006 12:42 am
    agree with aim-wsc

    800guy Master | Next Rank: 500 Posts Default Avatar
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    Post Mon Dec 25, 2006 9:31 am
    here's the OA. merry christmas!

    We first determine the number of integers less than 5,000 that are evenly divisible by 15. This can be found by dividing 4,999 by 15:

    = 4,999/15
    = 333 integers

    Now we will determine the number of integers evenly divisible by 21:

    = 4,999/21
    = 238 integers

    some numbers will be evenly divisible by BOTH 15 and 21. The least common multiple of 15 and 21 is 105. This means that every number that is evenly divisible by 105 will be divisible by BOTH 15 and 21. Now we will determine the number of integers evenly divisible by 105:

    = 4,999/105
    = 47 integers

    Therefore the positive integers less than 5000 that are not evenly divisible by 15 or 21 are 4999-(333+238-47)=4475

    800guy Master | Next Rank: 500 Posts Default Avatar
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    Post Mon Dec 25, 2006 9:32 am
    aim-wsc wrote:
    5000/15 = 333 quotient & 5 remainder

    5000/21 = 238 quotient & 2 remainder

    LCM for 15 & 21 =105

    5000/105 = 47 quotient

    5000-333-238+47 = 4476

    ANSWER :
    4475

    C'mon 800guy i dont think they will ask such questions...
    you're probably right, but it always helps to prepare for the worst

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